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O is the center of the regular octagon below. Find its area. Round to the nearest tenth if necessary. 9 A = 28.6 A = 27.6 A = 144.3 O A = 229.1

O is the center of the regular octagon below. Find its area. Round to the nearest tenth if necessary. 9 A = 28.6 A = 27.6 A = 144.3 O A = 229.1

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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### Problem Statement **\( O \) is the center of the regular octagon below. Find its area. Round to the nearest tenth if necessary.** **Diagram Description:** The diagram depicts a regular octagon with its center marked as \( O \). A line segment extends from the center \( O \) to one of the vertices of the octagon, measuring 9 units in length. ### Multiple Choice Options: - \( \bigcirc \) \( A = 28.6 \) - \( \bigcirc \) \( A = 27.6 \) - \( \bigcirc \) \( A = 144.3 \) - \( \bigcirc \) \( A = 229.1 \)
Transcribed Image Text:### Problem Statement **\( O \) is the center of the regular octagon below. Find its area. Round to the nearest tenth if necessary.** **Diagram Description:** The diagram depicts a regular octagon with its center marked as \( O \). A line segment extends from the center \( O \) to one of the vertices of the octagon, measuring 9 units in length. ### Multiple Choice Options: - \( \bigcirc \) \( A = 28.6 \) - \( \bigcirc \) \( A = 27.6 \) - \( \bigcirc \) \( A = 144.3 \) - \( \bigcirc \) \( A = 229.1 \)
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