O Figure Q3 (c) shows the X-ray diffraction patterns of Aluminum powder by CuK,- radiation. i. Sketch the (311) plane in cubic structure using miller indices solution. ii. Calculate the planar spacing, d hkl and angle, 0 hkl for (311) peak if the lattice constant, a is 0.404 nm and is 0.1542 nm. Note that the diffraction condition is 2dhkl sin 0 = n[]. iii. Determine whether the crystal structure of Aluminum powder belongs to bcc or fcc lattices. Justify your answer. (111) 100 A=0.1542 nm (CuK „-radiation) 80 60 (200) 40 (311) (220) 20 (222) (400) (331)(420) Ol 20 50 90 80 20 (degrees) 30 40 60 70 100 110 120 Fig. Q3 (c): X-ray diffraction pattern of Aluminum powder by CuK,- radiation. Inte nsity (arbitrary units)
O Figure Q3 (c) shows the X-ray diffraction patterns of Aluminum powder by CuK,- radiation. i. Sketch the (311) plane in cubic structure using miller indices solution. ii. Calculate the planar spacing, d hkl and angle, 0 hkl for (311) peak if the lattice constant, a is 0.404 nm and is 0.1542 nm. Note that the diffraction condition is 2dhkl sin 0 = n[]. iii. Determine whether the crystal structure of Aluminum powder belongs to bcc or fcc lattices. Justify your answer. (111) 100 A=0.1542 nm (CuK „-radiation) 80 60 (200) 40 (311) (220) 20 (222) (400) (331)(420) Ol 20 50 90 80 20 (degrees) 30 40 60 70 100 110 120 Fig. Q3 (c): X-ray diffraction pattern of Aluminum powder by CuK,- radiation. Inte nsity (arbitrary units)
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Question
![c) Figure Q3 (c) shows the X-ray diffraction patterns of Aluminum powder by CuK-
radiation.
i. Sketch the (311) plane in cubic structure using miller indices solution.
ii. Calculate the planar spacing, d hkl and angle, 0 hkl for (311) peak if the lattice
constant, a is 0.404 nm and I is 0.1542 nm. Note that the diffraction
condition is 2dhkl sin 0 = n].
iii. Determine whether the crystal structure of Aluminum powder belongs to bcc
or fcc lattices. Justify your answer.
(111)
100
A=0.1542 nm (CuK „-radiation)
80
60
(200)
40
(311)
(220)
20
(222)
(400) (331)(420)
20
30
40
50
60
70
80
90
100 110 120
20 (degrees)
Fig. Q3 (c): X-ray diffraction pattern of Aluminum powder by CuK_-
radiation.
Inte nsity (arbitrary units)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F900bf5f3-f79e-48f1-8892-bc364437bfbb%2F74687d12-252d-48e1-b42a-2d896d381490%2Flopdie_processed.jpeg&w=3840&q=75)
Transcribed Image Text:c) Figure Q3 (c) shows the X-ray diffraction patterns of Aluminum powder by CuK-
radiation.
i. Sketch the (311) plane in cubic structure using miller indices solution.
ii. Calculate the planar spacing, d hkl and angle, 0 hkl for (311) peak if the lattice
constant, a is 0.404 nm and I is 0.1542 nm. Note that the diffraction
condition is 2dhkl sin 0 = n].
iii. Determine whether the crystal structure of Aluminum powder belongs to bcc
or fcc lattices. Justify your answer.
(111)
100
A=0.1542 nm (CuK „-radiation)
80
60
(200)
40
(311)
(220)
20
(222)
(400) (331)(420)
20
30
40
50
60
70
80
90
100 110 120
20 (degrees)
Fig. Q3 (c): X-ray diffraction pattern of Aluminum powder by CuK_-
radiation.
Inte nsity (arbitrary units)
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