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O CONFIDENCE INTERVALS AND HYPOTHESIS TESTING Introduction to hypothesis tests for the population mean using... Over the years, the mean customer satisfaction rating at a local restaurant has been 65. The restaurant was recently remodeled, and now the management claims the mean customer rating, u, is not equal to 65. In a sample of 32 customers chosen at random, the mean customer rating is 74.5. ASsume that the population standard deviation of customer ratings is 22.7. Is there enough evidence to support the claim that the mean customer rating is different from 65? Perform a hypothesis test, using the 0.10 level of significance. (a) State the null hypothesis H, and the alternative hypothesis H. H u = 65 OSO D>0 H: u # 65 ロ=ロ ロロ (b) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. • The value of the test statistic is given by • The p-value is two times the area under the curve to the right of the value of the test statistic. Standard Normal Distribution Step 1: Select one-tailed or two-tailed. O One-tailed O Two-tailed 0.3- Step 2: Enter the test statistic. (Round to 3 decimal places.) 2.367 02

O CONFIDENCE INTERVALS AND HYPOTHESIS TESTING Introduction to hypothesis tests for the population mean using... Over the years, the mean customer satisfaction rating at a local restaurant has been 65. The restaurant was recently remodeled, and now the management claims the mean customer rating, u, is not equal to 65. In a sample of 32 customers chosen at random, the mean customer rating is 74.5. ASsume that the population standard deviation of customer ratings is 22.7. Is there enough evidence to support the claim that the mean customer rating is different from 65? Perform a hypothesis test, using the 0.10 level of significance. (a) State the null hypothesis H, and the alternative hypothesis H. H u = 65 OSO D>0 H: u # 65 ロ=ロ ロロ (b) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. • The value of the test statistic is given by • The p-value is two times the area under the curve to the right of the value of the test statistic. Standard Normal Distribution Step 1: Select one-tailed or two-tailed. O One-tailed O Two-tailed 0.3- Step 2: Enter the test statistic. (Round to 3 decimal places.) 2.367 02

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Not sure about part b and c
O CONFIDENCE INTERVALS AND HYPOTHESIS TESTING Introduction to hypothesis tests for the population mean using. Over the years, the mean customer satisfaction rating at a local restaurant has been 65. The restaurant was recently remodeled, and now the management claims the mean customer rating, µ, is not equal to 65. In a sample of 32 customers chosen at random, the mean customer rating is 74.5. ASsume that the population standard deviation of customer ratings is 22.7. Is there enough evidence to support the claim that the mean customer rating is different from 65? Perform a hypothesis test, using the 0.10 level of significance. (a) State the null hypothesis H, and the alternative hypothesis H,. H,: µ = 65 H: u 65 D=D (b) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. . The value of the test statistic is given by • The p-value is two times the area under the curve to the right of the value of the test statistic. Standard Normal Distribution Step 1: Select one-tailed or two-tailed. O One-tailed Two-tailed 0.3 Step 2: Enter the test statistic. (Round to 3 decimal places.) 2.367 0.2
Transcribed Image Text:O CONFIDENCE INTERVALS AND HYPOTHESIS TESTING Introduction to hypothesis tests for the population mean using. Over the years, the mean customer satisfaction rating at a local restaurant has been 65. The restaurant was recently remodeled, and now the management claims the mean customer rating, µ, is not equal to 65. In a sample of 32 customers chosen at random, the mean customer rating is 74.5. ASsume that the population standard deviation of customer ratings is 22.7. Is there enough evidence to support the claim that the mean customer rating is different from 65? Perform a hypothesis test, using the 0.10 level of significance. (a) State the null hypothesis H, and the alternative hypothesis H,. H,: µ = 65 H: u 65 D=D (b) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. . The value of the test statistic is given by • The p-value is two times the area under the curve to the right of the value of the test statistic. Standard Normal Distribution Step 1: Select one-tailed or two-tailed. O One-tailed Two-tailed 0.3 Step 2: Enter the test statistic. (Round to 3 decimal places.) 2.367 0.2
nypotlesis tests for the population mean using. Shel ndard Normal Distribution Step 1: Select one-tailed or two-tailed. O One-tailed O Two-tailed 0.3- Step 2: Enter the test statistic. (Round to 3 decimal places.) 2.367 02- Step 3: Shade the area represented by the p-value. Area = 0.991 0.1- Area = 0.991 Step 4: Enter the p-value. (Round to 3 decimal places.) 1.982 2- -2.367 N=2367 (c) Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the management. O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal to 65. O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal to 65. O Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal to 65. O Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal to 65.
Transcribed Image Text:nypotlesis tests for the population mean using. Shel ndard Normal Distribution Step 1: Select one-tailed or two-tailed. O One-tailed O Two-tailed 0.3- Step 2: Enter the test statistic. (Round to 3 decimal places.) 2.367 02- Step 3: Shade the area represented by the p-value. Area = 0.991 0.1- Area = 0.991 Step 4: Enter the p-value. (Round to 3 decimal places.) 1.982 2- -2.367 N=2367 (c) Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the management. O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal to 65. O Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal to 65. O Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal to 65. O Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal to 65.
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