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o as soon as possible.. && What is the velocity (magnitude and direction) of the ball at the maximum heigh, and if the fence is 3.50 m tall and 150. m away, how long does it take to reach the fence and how high above the ground is the ball when it reaches the fence? Does the ball c

o as soon as possible.. && What is the velocity (magnitude and direction) of the ball at the maximum heigh, and if the fence is 3.50 m tall and 150. m away, how long does it take to reach the fence and how high above the ground is the ball when it reaches the fence? Does the ball c

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What is the velocity (magnitude and direction) of the ball at the maximum heigh, and if the fence is 3.50 m tall and 150. m away, how long does it take to reach the fence and how high above the ground is the ball when it reaches the fence? Does the ball clear the fence?

b) Calculate how much time it takes to reach its maximum height, how high it goes, and how long it would take to reach the ground if there were no fence. On a separate page, draw the trajectory of the ball and show the positions of the ball and its velocity vectors at the origin, maximum height, and final position on the ground. (3 T= pts) 2vsin (37) T- 2x40x 0. 6 10 T=4.8 sec to tal time to flight t=플 = 4.8 %3D 2 t= 2.4 sec Time to reach the maximum height is 2.4sec Hmas = vesin (0) Zg h = vtsin? (37) 2. | 40sin(33)1" 20 h= 40 sin? (37) 140x 0.412 = 1.2 20 hz 1.2m Maximum heignt is 1.2m The time to reach the proective on the ground if there were no tence is equal b the flightime of the progectile. T=4.8 sec 4.8 sec it would take to reach the ground if there were no fence.
Transcribed Image Text:b) Calculate how much time it takes to reach its maximum height, how high it goes, and how long it would take to reach the ground if there were no fence. On a separate page, draw the trajectory of the ball and show the positions of the ball and its velocity vectors at the origin, maximum height, and final position on the ground. (3 T= pts) 2vsin (37) T- 2x40x 0. 6 10 T=4.8 sec to tal time to flight t=플 = 4.8 %3D 2 t= 2.4 sec Time to reach the maximum height is 2.4sec Hmas = vesin (0) Zg h = vtsin? (37) 2. | 40sin(33)1" 20 h= 40 sin? (37) 140x 0.412 = 1.2 20 hz 1.2m Maximum heignt is 1.2m The time to reach the proective on the ground if there were no tence is equal b the flightime of the progectile. T=4.8 sec 4.8 sec it would take to reach the ground if there were no fence.
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