A random sample of 44 taxpayers claimed an average of $9,903 in medical expenses for the year. Assume the population standard deviation for these deductions was $2,443. Construct confidence intervals to estimate the averagededuction for the population with the levels of significance shown below.a. 1%b.2%c. 10%a. The confidence interval with a 1% level of significance has a lower limit of $(Round to the nearest dollar as needed.)b. The confidence interval with a 2% level of significance has a lower limit of $(Round to the nearest dollar as needed.)c. The confidence interval with a 10% level of significance has a lower limit of $(Round to the nearest dollar as needed.)esc.6.FI2F2# 3F3S4F4and an upper limit of $and an upper limit of $and an upper limit of $%5F5A6MacBook AirTIEF6&7F7* CO8►11F89F90Time Remaining: 00:56:06F10F113+ 11NextF12Gdelete

Given: Sample size n = 44 Sample mean X = 9903 Population standard deviation σ = 2443 Formula Used:…

Answered: O A random sample of 44 taxpayers…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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you measure the weights of a random sample of twenty-five people. The sample mean is 60 kg. Suppose that the mean weights of people follow a normal distribution with an unknown mean and standard deviation of 5 kg. You compute a 95% confidence interval for μ. The 95% confidence interval for μ is?
man.2
a. interpret the corresponding 95% confidence intervals for both Birth weight and Age. b. What is the predicted average SBP of an infant born with birth weight 8lbs (128oz) measured at 3 days old? c. Calculate the Pearson correlation between Age and Birth weight, and test if this correlation is significant at the 0.05 level. Does this answer surprise you, why or why not?
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
The following data are the monthly salaries and the grade point averages for students who obtained a bachelor's degree in mathematics. GPA: 2.6, 3.4, 3.6, 3.2, 3.5, and 2.9; Monthly Salary: 3300, 3600, 4000, 3500, 3900, and 3600. Develop a 95% prediction interval for the expected value of y when x 3.6. Explain.
Title a. A random sample of 25 was drawn from a normal distribution with a standard deviation of 5. The... Description a. A random sample of 25 was drawn from a normal distribution with a standard deviation of 5. The sample mean is 80. Determine the 95% confidence interval estimate of the population mean. b. Repeat part (a) with a sample size of 100. c. Repeat part (a) with a sample size of 400. d. Describe what happens to the confidence interval estimate when the sample size increases.
For the data set below, calculate r, r2, and a 95 percent confidence interval in r units. Then write a one- to two sentence conclusion statement that includes whether the null hypothesis was rejected or not and whether there is a strong /weak/no relationship. Assume a two tailed hypothesis and α = .05. Case 1 Case 2 Case 3 Case 4 Case 5 Case 6 X 1.05 1.15 1.30 2.00 1.75 1.00 Y 2 2 3 4 5 2
A laboratory tested 85 chicken eggs and found that the mean amount of cholesterol was 191 milligrams. Assume that o = 16.2 milligrams. Construct a 95% confidence interval for the true mean cholesterol content, µ, of all such eggs. Round to one decimal place. O A. 186.9 to 195.1 milligrams B. 186.5 to 195.5 milligrams C. 188.1 to 193.9 milligrams D. 187.6 to 194.4 milligrams
Exercise 3. A personal manager has found that historically the scores on aptitude tests given to applicants for entry-level positions follow a normal distribution with a standard deviation of 32.4 points. A random sample of nine test scores from the current group of applicants had a mean score of 187.9 points. a. Find an 80% confidence interval for the population mean score of the current group of applicants. b. Based on these sample results a statistician found for the population mean a confidence interval extending from 165.8 to 210.0 points. Find the confidence level of this interval.
In order to estimate the average amount a customer spends on a meal in a major restaurant, data was collected from a sample of 30 customers. Suppose the population standard deviation is $3 . If the sample mean is $22, what is the 95% confidence interval for the population mean? Select one: a. [20.93 , 23.07] b. [20.59 , 23.41] c. [21.99 , 22.01] d. [20.95 , 23.05]
J 7
K In a random sample of eleven people, the mean driving distance to work was 22.3 miles and the standard deviation was 4.9 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean u. Interpret the results. Identify the margin of error. (Round to one decimal place as needed.) Construct a 95% confidence interval for the population mean. (Round to one decimal place as needed.) Interpret the results. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or a decimal. Do not round.) OA. It can be said that % of the population has a driving distance to work (in miles) that is between the interval's endpoints. O B. % of all random samples of eleven people from the population will have a mean driving distance to work (in miles) that is between the interval's endpoints. OC. With % confidence, it can be said that most driving distances…

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