O A certain form of "triangular' distribution has c.d.f.F(x) = 1- (1– x), 0<<1,%3Dwhich is plotted in Figure 1. (It is called a triangular distributionbecause its p.d.f. is a line which, together with the axes, forms atriangle.)Figure 1The c.d.f. F(x)(i) Calculate the value of the upper quartile for this distribution.(ii) On a copy of, or very rough sketch based on, Figure 1, show thevalues of a and its corresponding quantile la for the upper quartilethat you calculated in part (c)(i).(x)크

Answered: Image /qna-images/answer/e494e324-28b4-4d3c-916e-03f8e004f4ea.jpg

Answered: O A certain form of triangular'…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A sample of 3 measurements are taken and recorded: a =8, y = 10 and z = 7 The sample mean is: x = = 8.33 Fill in the table below. aj (a; - x)2 Ex: 5.34 Ex: 5.34 Ex: 5.34 82 = (z-z)*+(y-a)* +(z-z) Ex: 5.34 (z-2)*+(y-z)* +(z-) = Ex: 5.34
earch zy Section 4.2-MAT 240: A https://learn.zybooks.com/zybook/MAT-240-J5704-OL-TRAD-UG.23EW5/chapter/4/section/2?content_resource_id=5... AQ T X M >MAT 240: Applied Statistics home > 4.2: Normal distribution FI PARTICIPATION 4.2.2 Empirical rule. ACTIVITY Sign out ere to search In 2015, the College Board SAT mathematics score of high school seniors, which follow an approximately normal distribution, had a mean of 511 and a standard deviation of 120² 1) What percentage of seniors who took the test in 2015 scored between 271 and 751? O approximately 50% O approximately 68% O approximately 95% 2) What percentage of seniors who took the test in 2015 scored above 631? 3) What percentage of seniors who took the test in 2015 scored between 271 and 511? A- 2 O approximately 16% O approximately 68% O approximately 84% O approximately 68% O approximately 16% O approximately 47.5% 4) Should a score of 770 be considered unusual? O Yes O No F2 + 43 X D2L Homepage - Southern Ne X D2L 4-1…
The distribution of certain test scores is a nonstandard normal distribution with a mean of 80 and a standard deviation of 9. What are the values of the mean and a standard deviation after all test scores have been standardized by converting them to z-scores using z=(x-µ)/σ? A) The mean is 100 and the standard deviation is 10 B) The mean is 0 and the standard deviation is 1 C) The mean is 1 and the standard deviation is 0 D) The mean is 10 and the standard deviation is 100
A type of casting iron has Hall-Petch parameters: σ0 = 36.3 MPa and K = 6.5 MPa ∙ mm^−0.5. For a given sample, the grain size distribution is shown in the diagram below. Each bar represents the percentage of grains in particular size. First, estimate the average grain size based on concept of “weighted mean” (in case you do not know, search for this term). Then, apply Hall-Petch Equation to calculate the yield stress. (Note: 1 μm = 0.001 mm)
• Applying the empirical rule to a bell-shaped data distribution with u mately, what percentage of the data lie inside the interval [20, 80] (A) 95% = 50 and o = 15, approxi- (В) 68% (С) 99.7% (D) can't tell
Q: The frequency distribution of a sample taken from 60 different types of cars is shown below. Type Toyota Nissan BMW Hyundai GMC Frequency 18 12 11 9 (1) The type of this distribution is ungrouped) 10 .... frequency distribution. (grouped \ (2) The type of this measurement is ..... .... (nominal \ ordinal \ interval\ ratio) (3) The type of this variable is............... (quantity \ quality) (4) Find the Sample Size. (5) Find the percentage of BMW class. (6) Find the degree of GMC class.
Please answer number 6. Make sure to show work! Thanks.
stion 16: nts) A random sample of 200 psychology students was selected from a department's participant pool. A researchers determined each student's score on the NPI-16 and the number of his or her Facebook friends. The marginal distribution of NPI-16 scores was 4, with a standard deviation of 2. The marginal distribution "Facebook Friends" was 450, with a standard deviation of 200. The correlation between the two variables was .15. Assuming that NPI-16 is the predictor variable and Number of Facebook Friends is the outcome variable, compute the following: The lower limit of the 95% confidence interval around b. Note: Enter your answer to the second decimal place.
please list z score an the intervals like mean and standard devation. test stastic fortmula with values the procedure name the parameter in c level context and if its random or normal
es point(s) possible Workers at a certain soda drink factory collected data on the volumes (in ounces) of a simple random sample of 22 cans of the soda drink. Those volumes have a mean of 12.19 oz and a standard deviation of 0.14 oz, and they appear to be from a normally distributed population. If the workers want the filling process to work so that almost all cans have volumes between 11.98 oz and 12.70 oz, the range rule of thumb can be used to estimate that the standard deviation should be less than 0.18 oz. Use the sample data to test the claim that the population of volumes has a standard deviation less than 0.18 oz. Use a 0.05 significance level. Complete parts (a) through (d) below. b. Compute the test statistic. x²=0 (Round to three decimal places as needed.) c. Find the P-value. P-value= (Round to four decimal places as needed.) d. State the conclusion. the level of significance. There is evidence to conclude that the population Ho, because the P-value is standard deviation of…
d,e,f e) This result would be (usual, unusual) so the sample likely came from a population whose mean gestation period is(less, more, equal) to 266 days
3) Suppose test scores are measured by the Gaussian Normal Distribution N(X,75,10) calculate the following. a) Pr(80 < X < 90) b) Pr(50 < X < 70) c) The 95 th percentile

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