What is the IR and HNMRAndCNMR and mass O40001008060IR Spectrum(liquid film)4020v (cm')87 M = 146 (<1%)4080120 160m/e13C NMR Spectrum(20.0 MHz, CDCI, solution)proton decoupled200¹H NMR Spectrum(100 MHz, CDCI, solution)9% of base peak1030004313481760C200016001602001201200800Mass Spectrum240C6H1004280C-HsolventJill80the17 6 5 43Problem 45No significant UVabsorption above 220 nm-CH₂4011-CH₂TMS08 (ppm)TMS08 (ppm)2 1

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O 4000 100 80 60 IR Spectrum (liquid film) 40 20 v (cm') 87 M = 146 (<1%) 40 80 120 160 m/e 13C NMR Spectrum (20.0 MHz, CDCI, solution) proton decoupled 200 ¹H NMR Spectrum (100 MHz, CDC1, solution) 9 % of base peak 10 3000 43 134 8 1760 C 2000 1600 160 200 120 1200 800 Mass Spectrum 240 C6H1004 280 C-H solvent JIL 80 the 1 7 6 5 4 Problem 45 No significant UV absorption above 220 nm -CH₂ -CH₂ TMS 08 (ppm) TMS 0 8 (ppm) 40 3 2 1

O 4000 100 80 60 IR Spectrum (liquid film) 40 20 v (cm') 87 M = 146 (<1%) 40 80 120 160 m/e 13C NMR Spectrum (20.0 MHz, CDCI, solution) proton decoupled 200 ¹H NMR Spectrum (100 MHz, CDC1, solution) 9 % of base peak 10 3000 43 134 8 1760 C 2000 1600 160 200 120 1200 800 Mass Spectrum 240 C6H1004 280 C-H solvent JIL 80 the 1 7 6 5 4 Problem 45 No significant UV absorption above 220 nm -CH₂ -CH₂ TMS 08 (ppm) TMS 0 8 (ppm) 40 3 2 1

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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