Which of the following reactions is NOT correct? ### Nuclear Fusion ReactionsThe image presents a series of nuclear fusion reactions. Each reaction shows how various nuclei combine to form different products. The equations can be described as follows:1. \(\phantom{}^{2}_{1}\text{H} + \phantom{}^{2}_{0}\text{n} \rightarrow \phantom{}^{4}_{2}\text{He}\) In this reaction, two deuterium nuclei (\(\phantom{}^{2}_{1}\text{H}\)) and two neutrons (\(\phantom{}^{2}_{0}\text{n}\)) fuse to form a helium-4 nucleus (\(\phantom{}^{4}_{2}\text{He}\)). 2. \(\phantom{}^{6}_{3}\text{Li} + \phantom{}^{1}_{0}\text{n} \rightarrow \phantom{}^{4}_{2}\text{He} + \phantom{}^{3}_{1}\text{T}\) Here, a lithium-6 nucleus (\(\phantom{}^{6}_{3}\text{Li}\)) and a neutron (\(\phantom{}^{1}_{0}\text{n}\)) combine to produce a helium-4 nucleus (\(\phantom{}^{4}_{2}\text{He}\)) and a tritium nucleus (\(\phantom{}^{3}_{1}\text{T}\)). 3. \(\phantom{}^{1}_{1}\text{p} + \phantom{}^{2}_{1}\text{D} \rightarrow \phantom{}^{3}_{2}\text{He}\) In this reaction, a proton (\(\phantom{}^{1}_{1}\text{p}\)) and a deuterium nucleus (\(\phantom{}^{2}_{1}\text{D}\)) fuse to form a helium-3 nucleus (\(\phantom{}^{3}_{2}\text{He}\)). 4. \(\phantom{}^{2}_{1}\text{D} + \phantom{}^{3}_{1}\text{T} \rightarrow \phantom{}^{4}_{2}\text{He} + \phantom{}^{1}_{0}\text{n}\) This reaction involves a deuterium nucleus (\(\phantom{}^{2}_{1}\text{D}\)) and a tr

Answered: o 2}H + 2 }n → He o ŞLi + n+He + {T 41…

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Which of the following reactions is NOT correct?

### Nuclear Fusion Reactions

The image presents a series of nuclear fusion reactions. Each reaction shows how various nuclei combine to form different products. The equations can be described as follows:

1. \(\phantom{}^{2}_{1}\text{H} + \phantom{}^{2}_{0}\text{n} \rightarrow \phantom{}^{4}_{2}\text{He}\)

In this reaction, two deuterium nuclei (\(\phantom{}^{2}_{1}\text{H}\)) and two neutrons (\(\phantom{}^{2}_{0}\text{n}\)) fuse to form a helium-4 nucleus (\(\phantom{}^{4}_{2}\text{He}\)).

2. \(\phantom{}^{6}_{3}\text{Li} + \phantom{}^{1}_{0}\text{n} \rightarrow \phantom{}^{4}_{2}\text{He} + \phantom{}^{3}_{1}\text{T}\)

Here, a lithium-6 nucleus (\(\phantom{}^{6}_{3}\text{Li}\)) and a neutron (\(\phantom{}^{1}_{0}\text{n}\)) combine to produce a helium-4 nucleus (\(\phantom{}^{4}_{2}\text{He}\)) and a tritium nucleus (\(\phantom{}^{3}_{1}\text{T}\)).

3. \(\phantom{}^{1}_{1}\text{p} + \phantom{}^{2}_{1}\text{D} \rightarrow \phantom{}^{3}_{2}\text{He}\)

In this reaction, a proton (\(\phantom{}^{1}_{1}\text{p}\)) and a deuterium nucleus (\(\phantom{}^{2}_{1}\text{D}\)) fuse to form a helium-3 nucleus (\(\phantom{}^{3}_{2}\text{He}\)).

4. \(\phantom{}^{2}_{1}\text{D} + \phantom{}^{3}_{1}\text{T} \rightarrow \phantom{}^{4}_{2}\text{He} + \phantom{}^{1}_{0}\text{n}\)

This reaction involves a deuterium nucleus (\(\phantom{}^{2}_{1}\text{D}\)) and a tr

Expert Solution

Step 1

Since in any reaction,

1) total mass number of the reactants = total mass number of the products

2) total Atomic number of reactants = total atomic number of products

This is because both atomic and mass number represents the subatomic particle and in any reaction, subatomic particles neither can be created nor destroyed

Step 2

Mass number is represented by the top left number and atomic number by bottom left number written around the species

Here we have total mass number of product = 4

And mass number of reactant = 2 X 1 + 2 X 1 = 4 ( because we have 2 H and 2 n so multiplying by 2 with mass numbers)

And total atomic number of product = 2

And atomic number of reactant = 2 X 1 + 2 X 0 = 2

hence the condition is satisfied. => this is correct reaction

Step 3

Here we have total mass number of product = 4 + 3 = 7

And mass number of reactant = 6 + 1 = 7

And total atomic number of product = 3 + 0 = 3

And atomic number of reactant = 2+1 = 3

hence the condition is satisfied. => this is correct reaction

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