(Numerical Differentiation) Suppose we are given a function f(x) whose drivative is not known explicitly. We may, however, wish to still approximate the value of the derivative of ƒ at a fixed point. In order to do this, we could use the so-called second- order centered difſerence formula given by S(r+ h) – S(r – h) 2h S'(1) × Other approximations exist and are studied in numerical analysis (MAT 4020). diff_cdf Function: Input variables: an anonymous function representing f • a scalar representing the location z where the derivative is desired • a scalar representing the value of h to be used in the approximation Output variables: • a scalar representing the approximate value of f"(x) computed using the above formula A possible sample case is: » df = diff_cdf(@(x) sin(x), 0, 0.1) df = 0.99833 %3D

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make a code 

used mathlab if possible 

please dont uses if or return keep it basic 

(Numerical Differentiation) Suppose we are given a function f(x) whose drivative is
not known explicitly. We may, however, wish to still approximate the value of the
derivative of f at a fixed point. In order to do this, we could use the so-called second-
order centered difference formula given by
S(r+h) – S(x - h)
S'(1) =
2h
Other approximations exist and are studied in numerical analysis (MAT 4020).
diff_cdf Function:
Input variables:
• an anonymous function representing S
• a scalar representing the location r where the derivative is desired
• a scalar representing the value of h to be used in the approximation
Output variables:
• a scalar representing the approximate value of f'(x) computed using the
above formula
A possible sample case is:
> df = diff_cdf(@(x) sin(x), 0, 0.1)
df =
0.99833
Transcribed Image Text:(Numerical Differentiation) Suppose we are given a function f(x) whose drivative is not known explicitly. We may, however, wish to still approximate the value of the derivative of f at a fixed point. In order to do this, we could use the so-called second- order centered difference formula given by S(r+h) – S(x - h) S'(1) = 2h Other approximations exist and are studied in numerical analysis (MAT 4020). diff_cdf Function: Input variables: • an anonymous function representing S • a scalar representing the location r where the derivative is desired • a scalar representing the value of h to be used in the approximation Output variables: • a scalar representing the approximate value of f'(x) computed using the above formula A possible sample case is: > df = diff_cdf(@(x) sin(x), 0, 0.1) df = 0.99833
Expert Solution
Step 1

Code:

int_ctr(@(x) sin(x),0,0.1)
function df=diff_cdf(f,x,h)
   df=(f(x+h)-f(x-h))/(2*h)
end

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