Number of Farms A random sample of the number of farms (in thousands) in various states follows. Estimate the mean number of farms per state with 95%confidence. Assume 0 = 31. Round intermediate and final answers to one decimal place. Assume the population is normally distributed.809.578.4.64335495475040109786.5221156816487944Send data to Excel<µ<の

Given,sample size(n)=24sample mean(x)=45.167standard deviation(σ)=31α=1-0.95=0.05α2=0.025Z0.025…

Answered: Number of Farms A random sample of the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Exhibit 13-31 To test whether or not there is a difference between treatments A, B, C and D, a sample of 12 observations has been randomly assigned to the four treatments. You are given the results below. Treatment A B 2 C D 1.872 46.33 15.44 Observation 36 30 26 30 26 25 33 Refer to Exhibit 13-31. The mean square between treatments (MSTR) equals 20 28 28 22 34 28
Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…
3..
Exhibit 9-5 n = 16 HO: u z 80 x = 75.607 Hạ: u < 80 o = 8.246 Assume the population is normally distributed. 3. Refer to Exhibit 9-5. The test statistic equals .53 -2.131 -.53 2.131
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The histogram describes the height of students in a math class. Is the data univariate or bivariate? Is the skewness left, right, or normal?
Does Hypnotism Relieve Pain? The table shows the pain levels of patients before and after hypnotism. Pain level is measured on a cm scale. Assume that the two samples are randomly selected. At the 0.05 significance level, test the claim that the mean difference has increased after hypnotism.(Be sure to subtract in the same direction).
Listed below are pulse rates (beats per minute) from samples of adult males and females. Find the mean and median for each of the two samples and then compare the two sets of results. Does there appear to be a difference? Male: 98 60 59 66 69 73 52 88 63 74 61 84 58 59 52 Female: 83 75 93 94 87 63 94 89 93 79 77 85 74 70 76 ----- Find the means. The mean for males is beats per minute and the mean for females is beats per minute. (Type integers or decimals rounded to one decimal place as needed.)
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Find the mean, the median, and all modes for the data in the given frequency distribution. (Round your answers to one decimal place. If there is more than one mode, enter your answer as a comma-separated list. If an answer does not exist, enter DNE.) mean median mode(s) Points Scored by Lynn Points scored in abasketball game Frequency 2 9 6 8 7 9 10 7 11 2 13 4 14 2
8235#/full Pork... EmblemHealth Fin... ACCESS HRA - ACC... Account Link - ACC.. The mean score on this test is: 6.06 The median score on this test is: 6 Add Work Question 2 Find the five-number summary for the following data set. 87 84 89 88 89 81 82 89 88 84 Min Q1 Median Q3 Max 81 82 887.5 88 89 Add Work Question 3 The boxplots below shows salaries for Construction workers and Teachers Construction Teacher
The 2018 General Social Survey contains information on the number of 1F poor mental health days adults in the US had in the last month. The data arę below. Calculate the standard error of the mean number of poor health days for females. Table 1. Mean number of poor mental health days in the last 30 days by sex Male Female Total Mean S.D. 3.55 6.78 1408 3.02 4.06 6.43 7.07 678 730 Source GSS 2018 Your answer

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