(s).isZ:) --h2. (Balance this reaction In Acidic Solution):+3 -2*4= -4MnO4 (aq) + Br¯¯ (aq)+2+35e+ 8H+MnO4 (aq) →Mn(94)+2² t+ 2 Overture5x (Breaa) → Brace) +le) Oxidiation RecationнеP.5Br cace) → 5 Bra(e) the-2-Mn²+ (aq) + Br2 (1)+• 414₂0 (c) Reducation Recation• Cc56 +8H+Mn89 Mn5eaq) +5 Br(aq)be: 8H² + MnO4 (as) + 5 Br(aq) → Mn^ (ac) + 4H₂O(e) + 5 Br₂пойe-4-0Š2+→ Mn ² (ug) + 4H₂0 (4) +5B²₂ +5€сия)

Oxidation is defined as increase in oxidation state of the element.It can also be defined as addition of oxygen or removal of hydrogen.Reduction is defined as decrease in oxidation state of the element. It can also be defined as addition of hydrogen or removal of oxygen.An oxidising agent is the one which oxidises others and itself gets reduced by gaining electrons. For a species to be a good oxidizing agent, it should have higher reduction potential value.reducing agent is the one which reduces others and itself gets oxidised by losing electron. For a species to be a good reducing agent, it should have lower (more negative) reduction potential value.Br- ---> Br2 To balance bromine atoms, we multiply bromide by 2.2Br- ---> Br2 Now, to balance charge we add two electrons on product side.2Br- ---> Br2 + 2e-MnO4- ----> Mn2+ to balance oxygen atoms, we add 4 water molecules on product side and eight protons on reactant side.MnO4- + 8H+ ----> Mn2+ + 4H2ONow to balance charge, we add 5 electrons reactant side.MnO4- + 8H+ + 5e- ----> Mn2+ + 4H2O(aq) (aq) (aq) (l)Now, we have; 2Br- ---> Br2 + 2e- ....(1)MnO4- + 8H+ + 5e- ----> Mn2+ + 4H2O ..(2)Net reaction; 5 *(1) + 2*(2) multiplying and adding equations; 2MnO4- (aq) + 16 H+ (aq) + 10Br- (aq) ----> 2Mn2+ (aq) + 8H2O (l) + 5Br2 (l) Thus, balanced equation is; 2MnO4- (aq) + 16 H+ (aq) + 10Br- (aq) ----> 2Mn2+ (aq) + 8H2O (l) + 5Br2 (l)

Science

Chemistry

NU Z 2. (Balance this reaction In Acidic Solution): +3-2x4 = -4 MnO4 (aq) + Br¯¯ (aq) +2 +3 24 Se+8H+MnO4 (4) → Mn ² (aq) +²41 +₂0 (1) +2 ouest Charge 5x (Brcan) -2- +2 Mn²+ (aq) + Br2 (1) 5Br coa) 5Bra (4) the Reducation Recution → Brace) +le) Oxidiation Recation 58 (29) 56t+ +8H+Mn89 (94) +586(aq) → Mn 8H+MnO4; ((4) +5 Br (ug) - Mn ² (ac) + 4H₂O(c) +5B(₂ 2+ →Mn" (us) + 4H₂0 (4) +5B6₂ +50 (44)

NU Z 2. (Balance this reaction In Acidic Solution): +3-2x4 = -4 MnO4 (aq) + Br¯¯ (aq) +2 +3 24 Se+8H+MnO4 (4) → Mn ² (aq) +²41 +₂0 (1) +2 ouest Charge 5x (Brcan) -2- +2 Mn²+ (aq) + Br2 (1) 5Br coa) 5Bra (4) the Reducation Recution → Brace) +le) Oxidiation Recation 58 (29) 56t+ +8H+Mn89 (94) +586(aq) → Mn 8H+MnO4; ((4) +5 Br (ug) - Mn ² (ac) + 4H₂O(c) +5B(₂ 2+ →Mn" (us) + 4H₂0 (4) +5B6₂ +50 (44)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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