nsider the following statement. For all sets A and B, AC U BC C (A U B)C. e following is a proposed proof for the statement. 1. Suppose A and B are any sets, such that x EAC UBC. 2. Then x E AC or x E BC by definition of union. 3. It follows that x A or x B by definition of complement, and so x AU B by definition of union. 4. Thus x E (A U B)C by definition of complement, and hence AC U BCC (AUB) by definition of subset. entify the error(s) in the proposed proof. (Select all that apply.) The proof does not handle the case when ACB. The proof does not handle the case when BCA. The proof assumes what is to be proved. It is possible for x E AC U BC to be true and x EAC or x E BC to be false. It is possible for x # A or x B to be true and x A U B to be false.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Consider the following statement.
For all sets A and B, AC U BCC (AUB)C.
The following is a proposed proof for the statement.
1. Suppose A and B are any sets, such that x E AC U BC.
2. Then x E AC or x E BC by definition of union.
U
3. It follows that x A or x B by definition of complement, and so
x & AU B by definition of union.
4. Thus x E (A U B) by definition of complement, and hence
AC U BCC (AUB) by definition of subset.
Identify the error(s) in the proposed proof. (Select all that apply.)
The proof does not handle the case when AC B.
The proof does not handle the case when BCA.
The proof assumes what is to be proved.
It is possible for x E AC U BC to be true and x E AC or x E BC to be false.
It is possible for x A or x & B to be true and x AU B to be false.
X
Transcribed Image Text:Consider the following statement. For all sets A and B, AC U BCC (AUB)C. The following is a proposed proof for the statement. 1. Suppose A and B are any sets, such that x E AC U BC. 2. Then x E AC or x E BC by definition of union. U 3. It follows that x A or x B by definition of complement, and so x & AU B by definition of union. 4. Thus x E (A U B) by definition of complement, and hence AC U BCC (AUB) by definition of subset. Identify the error(s) in the proposed proof. (Select all that apply.) The proof does not handle the case when AC B. The proof does not handle the case when BCA. The proof assumes what is to be proved. It is possible for x E AC U BC to be true and x E AC or x E BC to be false. It is possible for x A or x & B to be true and x AU B to be false. X
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