O Question 5 - Chapter 19 - Conne xb Answered: . Which phase change xmeducation.com/ext/map/index.html? con=con&external_browser3D0&launchUrl=https%253A%252F%252Fysu.blackboard.com%252FwebapiSavedComplete the statements about the redox reaction below.2Au**(aq) + 3Cd(s) → 2Au(s) + 3Cd*(aq)Half-reactions:Au3 (aq) + 3e Au(s)Cd2 (aq) + 2e Cd(s)E° = +1.50 VE° = -0.40 VCd(s)is being oxidized.voltaic6.is being reduced.Au(aq)Au(s)is acting as an reducing agent.4.3is acting as an oxidizing agent.Cd2 (aq)moles of electrons are transferred.electrolyticThe reaction is a(n)cell.< Prev5 of 10Nexte to searcher

Answer: 1) Cd is being oxidised . Because oxidation state of CD is increased. 2) Au3+ is being…

ns: Au (aq) + 3e Au(s) E = +1.50 V Cd2*(aq) + 2e Cd(s) E =-0.40 V is being oxidized. is being reduced. is acting as an reducing agent. is acting as an oxidizing agent. moles of electrons are transferred. ytic The reaction is a(n) cell.

ns: Au (aq) + 3e Au(s) E = +1.50 V Cd2*(aq) + 2e Cd(s) E =-0.40 V is being oxidized. is being reduced. is acting as an reducing agent. is acting as an oxidizing agent. moles of electrons are transferred. ytic The reaction is a(n) cell.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

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