1 and 3 (4, 2)grapX-y = 2dy27.dxfunc(1, –1)-x-y = 2(а)(b)(c)(1, –1)(a)(b)FIGURE 14.36 Region of Example 7 with vertical and horizontal strips.28.Perhaps the use of horizontal strips can simplify our work. In Figure 14.36(b), the widthof the strip is Ay. The rightmost curve is always x – y = 2 (or x = y + 2), and theleftmost curve is always yis [(y + 2) – y²]Ay, so the total area isfunc(а)= x (or x = y²). Therefore, the area of the horizontal strin(b)(c)%3D(d)| v +2 - y) dy =Clearly, the use of horizontal strips is the most desirable approach to solving the prob-area =9.29.%3Dfundlem. Only a single integral is needed, and it is much simpler to compute.(a)(b)(c)(d)PROBLEMS 14.9Now Work Problem 57 430.In Problems 1–24, use a definite integral to find the area of theregion bounded by the given curve, the x-axis, and the given lines.In each case, first sketch the region. Watch out for areas of regions2. y =x+5, x = 2, x = 4%3D3. y = 3x, x= 1, x= 3that are below the x-axis.4. y = x, x = 2, x = 3%3D1. y = 5x + 2, x= 1,6. y = x² – 2x, x=-15. y =x+x² +x², x= 1(b)%3Dx = -3,%3Dcert%3D7. y = 3x2 – 4x, x = -1x = -2,(c)LEGO

Given:- y = 5x+2, x = 1 and x= 4 y = 3x2 , x = 1 and x = 3 To find:- Area bounded by given…

Now Work Problem PROBLEMS 14.9 In Problems 1–24, use a definite integral to find the area of the region bounded by the given curve, the x-axis, and the given lines. In each case, first sketch the region. Watch out for areas of regions that are below the x-axis. 2. y = x+ 5, x= 2, x= 4 3. y = 3x, x = 1, 4. y = x, x = 2, x = 3 5. y = x+x² +x, %3D %3D 6. y = x² – 2x, x = -3, x = –1 1. y = 5x + 2, x= 1, X = 4 7. y = 3x - 4x, x = -2, x = -1