The force on an object in uniform circular motion isgiven by F = m v² / r. Now the two objects move at the same speed aroundthe same circle but have different masses m, and m2where m, = 2 m,. What is the ratio of the forces onthe two objects?Select one:O A. F1/ F2 = 1O B. F / F2 = 2OC. F/F2 = 4O D. F/F2 =1/2O E. F1/F2 =1/4OF. I can't eliminate any choices.

Since they revolve around the same circle and have the same speed, the radius and speed is equal for…

Now the two objects move at the same speed around the same circle but have different masses m, and m2 where m, = 2 m2. What is the ratio of the forces on the two objects? Select one: O A. F1/ F2 = 1 O B. F1/ F2 = 2 O C. F1/F2 = 4 O D. F1/ F2 =1/2 O E. F1/F2 =1/4 O F. I can't eliminate any choices.

Now the two objects move at the same speed around the same circle but have different masses m, and m2 where m, = 2 m2. What is the ratio of the forces on the two objects? Select one: O A. F1/ F2 = 1 O B. F1/ F2 = 2 O C. F1/F2 = 4 O D. F1/ F2 =1/2 O E. F1/F2 =1/4 O F. I can't eliminate any choices.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.

Question

The force on an object in uniform circular motion is
given by F = m v² / r.

Now the two objects move at the same speed around
the same circle but have different masses m, and m2
where m, = 2 m,. What is the ratio of the forces on
the two objects?
Select one:
O A. F1/ F2 = 1
O B. F / F2 = 2
OC. F/F2 = 4
O D. F/F2 =1/2
O E. F1/F2 =1/4
OF. I can't eliminate any choices.

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