Now the system is adjusted so the spring launcher sits aims upward at an angle = 30° from horizontal. The sphere is launched from the same height h = 1.7 m above the floor. The bucket is moved to a new 2.5 m from the end of the platform and is h = 1.02 m above the floor as shown in the location, db,new figure. - What must be the launch velocity vo of the ball bearings from the launcher so that they land in the bucket?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Platform
v0 =
0
Vo
= 4.39 m/s
9.49 m/s
VO
4.24 m/s
Vo
(e) vo = 12.61 m/s
hi
O
db
O
hp
Now the system is adjusted so the spring launcher sits aims upward at an angle = 30° from horizontal.
The sphere is launched from the same height h = 1.7 m above the floor. The bucket is moved to a new
location, db,new = 2.5 m from the end of the platform and is h = 1.02 m above the floor as shown in the
figure.
bucket
What must be the launch velocity vo of the ball bearings from the launcher so that they land in the bucket?
= 4.94 m/s
Box
Transcribed Image Text:Platform v0 = 0 Vo = 4.39 m/s 9.49 m/s VO 4.24 m/s Vo (e) vo = 12.61 m/s hi O db O hp Now the system is adjusted so the spring launcher sits aims upward at an angle = 30° from horizontal. The sphere is launched from the same height h = 1.7 m above the floor. The bucket is moved to a new location, db,new = 2.5 m from the end of the platform and is h = 1.02 m above the floor as shown in the figure. bucket What must be the launch velocity vo of the ball bearings from the launcher so that they land in the bucket? = 4.94 m/s Box
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