Now suppose our study involv compute d by subtracting the weight gain for each bedrest patient from the weigh gain for the matched patient treatec with the antibiotic. The average difference d = -3002 g with standard deviation s, = 3081 g. (We continue to use a two- tailed test and level of significance 0.05.) The degrees of freedom is There are two critical numbers, and t, 12 is The value of the test statistic is TS =

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Chapter1: Starting With Matlab
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Solve these 2 questions and explain your answer please
Again use the critical numbers to determine
whether there is evidence (in this second study)
that the mean weight gain is different for the
two groups. Explain how you decided, using
complete sentences.
O A. There is evidence at level of significance 0.05 that the
mean weight gain is different for the two groups.
O B. There is not evidence at level of significance 0.05 that
the mean weight gain is different for the two groups.
Transcribed Image Text:Again use the critical numbers to determine whether there is evidence (in this second study) that the mean weight gain is different for the two groups. Explain how you decided, using complete sentences. O A. There is evidence at level of significance 0.05 that the mean weight gain is different for the two groups. O B. There is not evidence at level of significance 0.05 that the mean weight gain is different for the two groups.
Now suppose our study involves n = 150 matched palrs We
compute d by subtracting the weight gain for each bedrest
patient from the weigh gain for the matched patient treated
with the antibiotic. The average difference d = -3002 g with
standard deviation S, = 3081 g. (We continue to use a two-
tailed test and level of significance 0.05.)
The degrees of freedom is
There are two critical numbers, and t, 2 is
D.
The value of the test statistic is TS =
Transcribed Image Text:Now suppose our study involves n = 150 matched palrs We compute d by subtracting the weight gain for each bedrest patient from the weigh gain for the matched patient treated with the antibiotic. The average difference d = -3002 g with standard deviation S, = 3081 g. (We continue to use a two- tailed test and level of significance 0.05.) The degrees of freedom is There are two critical numbers, and t, 2 is D. The value of the test statistic is TS =
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