Discrete Math I need help with the second part of this question. The first question is all correcct. I need help with the second part as the answers I've provided for the 2nd part of this question is wrong. Idk why. **Consider the Statement:**For any numbers \( a \) and \( b \), if \( a + b \) is odd, then either \( a \) or \( b \) is odd.**First, give a valid proof of the statement using proof by contrapositive. Drag 3 of the statements below to the right column.****Statements to choose from:**1. But then \( a + b \) is both even and odd, a contradiction.2. Let \( a \) and \( b \) be integers and assume that \( a + b \) is odd but \( a \) and \( b \) are both even.3. Let \( a \) and \( b \) be integers and assume that if \( a + b \) is odd, then either \( a \) or \( b \) is odd.4. Let \( a \) and \( b \) be integers and assume both are even.5. The sum of two even integers must also be even.6. Therefore \( a + b \) is even.**Your Proof: Put chosen statements in order in this column.**1. Let \( a \) and \( b \) be integers and assume both are even.2. The sum of two even integers must also be even.3. Therefore \( a + b \) is even.**Now prove the statement using a proof by contradiction.****Statements to choose from:**1. Let \( a \) and \( b \) be integers and assume that if \( a + b \) is odd, then either \( a \) or \( b \) is odd.2. Let \( a \) and \( b \) be integers and assume \( a + b \) is odd.3. Let \( a \) and \( b \) be integers and assume both are even.4. Let \( a \) and \( b \) be integers and assume that \( a + b \) is odd but \( a \) and \( b \) are both even.5. The sum of two even integers must also be even.6. Therefore \( a + b \) is even.7. But then \( a + b \) is both even and odd, a contradiction.**Your Proof: Put chosen statements in order in this column.**1. Let \( a \) and \( b \) be integers and assume

Now prove the statement using a proof by contradiction. Statements to choose from: Your Proof: Put chosen statements in order in this column. Let a and b be integers and assume that Let a and b be integers and assume that if a + b is odd, then either a or b is odd. a +b is odd but a and b are both even. Let a and b be integers and assume a + b is odd. The sum of two even integers must also be even. Let a and b be integers and assume both are even. Therefore a + b is even. But then a + b is both even and odd, a contradiction.

Now prove the statement using a proof by contradiction. Statements to choose from: Your Proof: Put chosen statements in order in this column. Let a and b be integers and assume that Let a and b be integers and assume that if a + b is odd, then either a or b is odd. a +b is odd but a and b are both even. Let a and b be integers and assume a + b is odd. The sum of two even integers must also be even. Let a and b be integers and assume both are even. Therefore a + b is even. But then a + b is both even and odd, a contradiction.

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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