Now integrate and simplify V = 2π 2x (64 V = 2π = 2π 16 = 2x [64. = 2π 3 4096 3 2 -√³ (8 2048 X T (8 - x)(16x-2x²) dx. x x - 32x² + 2x³) dx X -32x³ + 2x400 3 Jo - 32 3 + X
Now integrate and simplify V = 2π 2x (64 V = 2π = 2π 16 = 2x [64. = 2π 3 4096 3 2 -√³ (8 2048 X T (8 - x)(16x-2x²) dx. x x - 32x² + 2x³) dx X -32x³ + 2x400 3 Jo - 32 3 + X
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Now integrate and simplify V = 2π
8
= 2F. 6³ ( 64
V 2π
= 2π
16
= 2x 64.
= 2π
3
4096
3
2
'8
277 ³8 (8
2048
(8 - x)(16x - 2x²) dx.
T
× x − 32x² + 2x³) dx
X =²_321² + 2x² 10
2x478
3
4
x - 32²
3
x
1
× + ·|
2
X
]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0fe31802-9208-4057-b76d-48d59452148a%2F50953475-ee06-4a2a-9788-bbb9f23cb24e%2F5fm5g7_processed.png&w=3840&q=75)
Transcribed Image Text:Now integrate and simplify V = 2π
8
= 2F. 6³ ( 64
V 2π
= 2π
16
= 2x 64.
= 2π
3
4096
3
2
'8
277 ³8 (8
2048
(8 - x)(16x - 2x²) dx.
T
× x − 32x² + 2x³) dx
X =²_321² + 2x² 10
2x478
3
4
x - 32²
3
x
1
× + ·|
2
X
]
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