Now complete the chi-square test to determine if the Hardy-Weinberg equilibrium has been violated, i.e., evolution has occurred in the population. Use data from generations 3 and 4 to complete the chi-square test. Your TA will help you 2 equencies. (0 – E) E Chi-square table Genotype AA Genotype Aa Genotype aa df P = 0.05 3.84 Observed counts (generation 4) 11 2 5.99 3 7.82 Expected counts (generation 4) 5 4 9.49 (observed – expected) 1 -2 11 (observed – expected)? 4 (observed – expected)? / expected Σ (sum) =
Now complete the chi-square test to determine if the Hardy-Weinberg equilibrium has been violated, i.e., evolution has occurred in the population. Use data from generations 3 and 4 to complete the chi-square test. Your TA will help you 2 equencies. (0 – E) E Chi-square table Genotype AA Genotype Aa Genotype aa df P = 0.05 3.84 Observed counts (generation 4) 11 2 5.99 3 7.82 Expected counts (generation 4) 5 4 9.49 (observed – expected) 1 -2 11 (observed – expected)? 4 (observed – expected)? / expected Σ (sum) =
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
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Transcribed Image Text:Now complete the chi-square test to determine if the Hardy-Weinberg equilibrium has been violated, i.e.,
evolution has occurred in the population. Use data from generations 3 and 4 to complete the chi-square test.
Your TA will help you
equencies.
(0 - E)
x² = E
E
Chi-square table
Genotype AA
Genotype Aa
Genotype aa
df
P = 0.05
3.84
Observed counts (generation 4)
11
4
2
5.99
7.82
Expected counts (generation 4)
4
9.49
11
(observed – expected)
-2
(observed – expected)?
4
(observed – expected)? / expected
Σ (sum)
%3D
Expert Solution
Step 1
Null hypothesis: there is no significant difference between observed and expected frequencies.
sum of expected should be equal to sum of observed frequencies.
Total observed frequency = 21
Expected count for Genotype Aa is 11 (21-5-5)
(observed- expected) for Aa= 11-11 = 0
| AA | Aa | aa | |
| observed | 6 | 11 | 4 |
| expected | 5 | 11 | 5 |
| (observed- expected) | 1 | 0 | -2 |
| (observed- expected)2 | 1 | 0 | 4 |
| (observed- expected)2/ expected | 0.2 | 0 | 0.8 |
| sum | 1 (0.2+0+0.8) |
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