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Notice that when h = 0, the denominator of lim 2(x + h)² = 2x² h→0 h Recall that if the numerator is also zero when h = 0, the limit has the indeterminate form (-) and h is a common factor of the numerator and denominator. To determine if the numerator is zero when h = 0, replace h with 0 in the numerator of the limit and simplify. 2(x + h)²2x² = 2(x + 0)² - 2x² Thus, lim h-0 = is zero. 2(x + h)² - 2x² h ---Select--- ¹ (9) ² at h= 0 and h ---Select--- a common factor of the numerator and denominator. the indeterminate form

Notice that when h = 0, the denominator of lim 2(x + h)² = 2x² h→0 h Recall that if the numerator is also zero when h = 0, the limit has the indeterminate form (-) and h is a common factor of the numerator and denominator. To determine if the numerator is zero when h = 0, replace h with 0 in the numerator of the limit and simplify. 2(x + h)²2x² = 2(x + 0)² - 2x² Thus, lim h-0 = is zero. 2(x + h)² - 2x² h ---Select--- ¹ (9) ² at h= 0 and h ---Select--- a common factor of the numerator and denominator. the indeterminate form

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Notice that when h = 0, the denominator of lim h→0 Recall that if the numerator is also zero when h = 0, the limit has the indeterminate form and h is a common factor of the numerator and denominator. Thus, lim h→0 2(x + h)² - 2x² h To determine if the numerator is zero when h = 0, replace h with 0 in the numerator of the limit and simplify. 2(x + h)² - 2x² = 2(x + 0)² – 2x² 2(x + h)² - 2x² h is zero. ---Select--- 0 the indeterminate form (-) at h = 0 and h ---Select-- a common factor of the numerator and denominator. 0
Transcribed Image Text:Notice that when h = 0, the denominator of lim h→0 Recall that if the numerator is also zero when h = 0, the limit has the indeterminate form and h is a common factor of the numerator and denominator. Thus, lim h→0 2(x + h)² - 2x² h To determine if the numerator is zero when h = 0, replace h with 0 in the numerator of the limit and simplify. 2(x + h)² - 2x² = 2(x + 0)² – 2x² 2(x + h)² - 2x² h is zero. ---Select--- 0 the indeterminate form (-) at h = 0 and h ---Select-- a common factor of the numerator and denominator. 0
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