Notice that when h = 0, the denominator of lim 2(x + h)² = 2x² h→0 h Recall that if the numerator is also zero when h = 0, the limit has the indeterminate form (-) and h is a common factor of the numerator and denominator. To determine if the numerator is zero when h = 0, replace h with 0 in the numerator of the limit and simplify. 2(x + h)²2x² = 2(x + 0)² - 2x² Thus, lim h-0 = is zero. 2(x + h)² - 2x² h ---Select--- ¹ (9) ² at h= 0 and h ---Select--- a common factor of the numerator and denominator. the indeterminate form

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