### Required Information**NOTE:** This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Determine the \( h_{fg} \) of refrigerant-134a at 20°F. Use data from the tables. The gas constant of refrigerant-134a is \( R = 0.01946\, \text{Btu/lbm} \cdot \text{R} \).Consider the Clapeyron equation for calculations. (You must provide an answer before moving on to the next part.)The \( h_{fg} \) of refrigerant-134a at 20°F is \_\_\_\_ Btu/lbm.

The refrigerant is The temperature is The gas constant is

Answered: NOTE: This is a multi-part question.…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Using the following information, determine the vapor pressure of water at 300 °C. Note: We started this problem in week 6 lecture 3. Please refer to the lecture to get started on this problem. You only need to show your work starting from where the lecture left off. H₂0 at T = 179.88 degrees C the vapor pressure is PSAT = 10 bar. The enthalpy of vaporization is 2014.59 kJ/kg V = 0.1944 m³/kg V¹ = 0.001127 m³/kg The equation we left off on in class was, cpf 1 [P² psat dpsat pi psat Tf 1 ∆vapH (TF 1 RAZ Ti dT T2a
*29. ssm The drawing refers to one mole of a monatomic ideal gas and shows a process that has four steps, two isobaric (A to B, C to D) and two isochoric (B to C, D to A). Complete the following table by calculating AU, W, and Q (including the algebraic signs) for each of the four steps. B -800.0-K isotherm -400.0-K isotherm 200.0-K isotherm D Volume Pressure
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Newton's Law of cooling states that the rate at which heat is lost by a heated body is proportional to the difference in temperature between the body and the surrounding medium. Match the following statements/phrases with the corresponding item in the drop down box. Choices in the box 1. In accordance with the stated law obove, we have the equation? 2. If a thermometer is taken outdoors where the temperoture is 5 deg C, from a room in which the temperature is 20 deg C and the reading drops 10 deg C in one minute, the working equation is? 3. In the obove problem, separoting the variables and integrating will result to? 4. In the obove problem, how long, in minutes, after its removal from the room will the reading be 6 deg C? 5. In the obove problem, ofter 30 seconds, whot will be the thermometer reading? 5.2 dT(body temp)/dt = k(Temp of medium - 5) dr(body temp)/dt = k(Temp of body - Temp of medium) Temp of body = Cenkt +5 2.5 13.7 dr(body temp)/dt = k(Temp of medium - Temp of body)…
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Use the 3 relations (equations) below to relate T(°F) to T(°C). Then, find out, at what temperature a Fahrenheit and a Celciusthermometer would read the same numerical value.
A heat pump is an electrical device that heats a building by pumping heat in from the cold outside. In other words, it's the same as a refrigerator, but its purpose is to warm the hot reservoir rather than to cool the cold reservoir (even though it does both). Let us define the following standard symbols, all taken to be positive by convention:Th = temperature inside buildingTe = temperature outsideQh heat pumped into building in 1 day Qe = heat taken from outdoors in 1 dayW = electrical energy used by heat pump in 1 day Explain why a heat pump is better than an electric furnace, which simply converts electrical work directly into heat. (Include some numerical estimates. )
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