I am going to post this 3rd time are u blind I said simply arrange these steps means step1 then 2 and so onThese are total 15 steps arrange in aa sequence plz for God sake what are u doing waste my question many times By dragging statements from the left column to the right column below, give a proof by induction of the following statement:The correct proof will use 8 of the statements below.Statements to choose from:Let P(n) be the statement, "a, = 9"-1".Therefore, by the Principle of MathematicalInduction, P(n) ise for all n ≥ 1.Then ak+1=9ak + 8, so P(k+ 1) is true.Then = 9 - 1.Now assume that P(k+ 1) is true.Note that a = 90-1-1-1=0, as required.Note that a₁ = 9ao + 8.Now assume that P(n) is true for all n ≥ 0.Then 9+1 -1 = 9(91)+8, which is true.an = 9"-1 is a solution to the recurrence relation a, 9a-1 +8 with ag = 0.Your Proof: Put chosen statements in order in thiscolumn and press the Submit Answers button. Note that a = 90-1=1-1=0, as required.Note that a₁ = 9a0 +8.Now assume that P(n) is true for all n ≥ 0.Then 9+1 -1 = 9(9k-1)+8, which is true.This simplifies toak+1 = 9+19+8 = 9+1 - 1Now assume that P(k) is true for an arbitraryinteger 1.Let P(n) be the statement, "a,,= 9" - 1 is asolution to the recurrence relation an = 9an-1 +8with a = 0."Thus P(k+ 1) is true.By the recurrence relation, we haveak+1 = 9ak + 8 = 9(9k-1) + 8Thus P(k) is true for all k.

Answered: Image /qna-images/answer/0aeace58-dca7-4e71-9320-5041903f46a3.jpg

Note that a = 90-1-1-1=0, as required. Note that a₁ = 9a0 +8. Now assume that P(n) is true for all n ≥ 0. Then 9+1 -1 = 9(91) +8, which is true. This simplifies to ak+1 = 9+19+8 = 9+1 - 1 Now assume that P(k) is true for an arbitrary integer 1. w Let P(n) be the statement, "a, = 9" - 1 is a solution to the recurrence relation an = 9an-1 +8 with a = 0." Thus P(k+ 1) is true. By the recurrence relation, we have

Note that a = 90-1-1-1=0, as required. Note that a₁ = 9a0 +8. Now assume that P(n) is true for all n ≥ 0. Then 9+1 -1 = 9(91) +8, which is true. This simplifies to ak+1 = 9+19+8 = 9+1 - 1 Now assume that P(k) is true for an arbitrary integer 1. w Let P(n) be the statement, "a, = 9" - 1 is a solution to the recurrence relation an = 9an-1 +8 with a = 0." Thus P(k+ 1) is true. By the recurrence relation, we have

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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