NOTE: for this question, give all answers with 4 significant figures.A motion detector measures distance to the nearest object by using a speaker and a microphone. Thespeaker clicks 30 times a second. The microphone detects the sound bouncing back from the nearest objectin front of it. The computer calculates the time delay between the making of the sound and receiving theecho. It knows the speed of sound (about 343 m/s at room temperature) and from that, it can calculate thedistance to the object from the time delay.A. If the nearest object in front of the detector is too far away, the echo will not get back before a second click is emitted. Once thathappens, the computer has no way of knowing that the echo isn't an echo from the second click and the detector doesn't give correctresults anymore. Once the speaker emits a click, how much time does the echo have to return to the microphone before the next clickis emitted?0.03333What's the furthest away the object can be so that the echo returns before the next click is emitted?5.716mB. The speed of sound changes a little bit with temperature. Let's try to get an idea of how important this is. At room temperature (72°F)the speed of sound is about 343 m/s. At 62°F it is about 1% smaller.Suppose we are measuring an object that is 2.7 meters away from the detector at 72°F. What is the time delay At that the computerdetects before the echo returns?Now suppose the object is still 2.7 m from the detector, but the temperature is 62°F. What is the speed of sound at this temperature?m/sAt this speed, what is the time delay At that the computer detects before the echo returns?If the computer detects this time delay, but calculates the distance using the speed of sound at 72°F (because it doesn't know thetemperature), what is the object's distance that the computer would report?m

Answered: Image /qna-images/answer/9dbff26d-463a-451e-8a82-0fdd35f1d01d.jpg

NOTE: for this question, give all answers with 4 significant figures. A motion detector measures distance to the nearest object by using a speaker and a microphone. The speaker clicks 30 times a second. The microphone detects the sound bouncing back from the nearest object in front of it. The computer calculates the time delay between the making of the sound and receiving the echo. It knows the speed of sound (about 343 m/s at room temperature) and from that, it can calculate the distance to the object from the time delay. A. If the nearest object in front of the detector is too far away, the echo will not get back before a second click is emitted. Once that happens, the computer has no way of knowing that the echo isn't an echo from the second click and the detector doesn't give correct results anymore. Once the speaker emits a click, how much time does the echo have to return to the microphone before the next click is emitted? 40.03333 S What's the furthest away the object can be so that the echo returns before the next click is emitted? 45.716 m

NOTE: for this question, give all answers with 4 significant figures. A motion detector measures distance to the nearest object by using a speaker and a microphone. The speaker clicks 30 times a second. The microphone detects the sound bouncing back from the nearest object in front of it. The computer calculates the time delay between the making of the sound and receiving the echo. It knows the speed of sound (about 343 m/s at room temperature) and from that, it can calculate the distance to the object from the time delay. A. If the nearest object in front of the detector is too far away, the echo will not get back before a second click is emitted. Once that happens, the computer has no way of knowing that the echo isn't an echo from the second click and the detector doesn't give correct results anymore. Once the speaker emits a click, how much time does the echo have to return to the microphone before the next click is emitted? 40.03333 S What's the furthest away the object can be so that the echo returns before the next click is emitted? 45.716 m

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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