Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
![### Inverse Function Problem
**Note**: Enter your answer and show all the steps.
**Problem**: What is the inverse of the given relation?
\[ y = 3x + 12 \]
---
**Instructions**:
1. Swap the \( x \) and \( y \) in the equation.
2. Solve for \( y \).
**Steps to Solve**:
1. Replace \( y \) with \( x \) and \( x \) with \( y \):
\[ x = 3y + 12 \]
2. Solve for \( y \):
- Subtract 12 from both sides:
\[ x - 12 = 3y \]
- Divide both sides by 3:
\[ y = \frac{x - 12}{3} \]
Therefore, the inverse function is:
\[ y = \frac{x - 12}{3} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7c95e826-9fa5-432d-8485-6cd3f47807d4%2Faeb39e72-50fe-43b9-a924-db076dea4890%2Fz5cq5go_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Inverse Function Problem
**Note**: Enter your answer and show all the steps.
**Problem**: What is the inverse of the given relation?
\[ y = 3x + 12 \]
---
**Instructions**:
1. Swap the \( x \) and \( y \) in the equation.
2. Solve for \( y \).
**Steps to Solve**:
1. Replace \( y \) with \( x \) and \( x \) with \( y \):
\[ x = 3y + 12 \]
2. Solve for \( y \):
- Subtract 12 from both sides:
\[ x - 12 = 3y \]
- Divide both sides by 3:
\[ y = \frac{x - 12}{3} \]
Therefore, the inverse function is:
\[ y = \frac{x - 12}{3} \]
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