Normalise the following group of data using z score normalisation (200, 300, 400, 600, 1000) Which is the answer? a, b or c?
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Normalise the following group of data using z score normalisation (200, 300, 400, 600, 1000)
Which is the answer? a, b or c?
Step by step
Solved in 3 steps
- Perform the indicated operations. Perform the indicated operations. a. 01001011 AND 10101011 b. 100000011 AND 11101100 c. 11111111 AND 00101101 d. 01001011 OR 10101011 e. 10000011 OR 11101100 g. 11111111 OR 00101101 h. 01001011 01011Definition of a roundoff errorQ1: Draw the ASK signal? Q2: write a Matlab code to simulate a ASK modulation signal only.A. generate the following data (1001011).B. Tp= 2us.C. generate ASK signal.
- 1.) Is the following UPC numbers valid codes 0-51231-69421-5 2.) Find the check digit (d) for the UPC numbers 0-32692-03012 d 3.) Is the following Credit Card number valid? 4716 5868 1970 205 6 4.) Find the check digit (d) for the Credit Card number 5310 6275 7512 805 dConvert the following DFA to RE. 1 p. r r r r1. Write a report in a word file explaining how you did the project 1, also include the screenshots of your code and the output of what you got. 2. Please provide your code link from repl.it.com where I can run your code and see the output you got in Step 1. The ciphertext below was encrypted using a substitution cipher. In your favorite language (in C++ or Python) crack encrypted text below using frequency analysis lrvmnir bpr sumvbwvr jx bpr lmiwv yjeryrkbi jx qmbm wi bpr xjvni mkd ymibrut jx irhx wi bpr riirkvr jx ymbinlmtmipw utn qmumbr dj w ipmhh but bj rhnvwdmbr bpr yjeryrkbi jx bpr qmbm mvvjudwko bj yt wkbrusurbmbwjk lmird jk xjubt trmui jx ibndt wb wi kjb mk rmit bmiq bj rashmwk rmvp yjeryrkb mkd wbi iwokwxwvmkvr mkd ijyr ynib urymwk nkrashmwkrd bj ower m vjyshrbr rashmkmbwjk jkr cjnhd pmer bj lr fnmhwxwrd mkd wkiswurd bj invp mk rabrkb bpmb pr vjnhd urmvp bpr ibmbr jx rkhwopbrkrd ywkd vmsmlhr jx urvjokwgwko ijnkdhrii ijnkd mkd ipmsrhrii ipmsr w dj kjb drry ytirhx bpr xwkmh…
- 8- Convert to octal and then to decimal: (a) (10111011.1): (b) (1101101.011):In single precision (IEEE-754 standard), 8 bits are used for storing the exponent (the bias is 127), and 23 bits are used for storing the mantissa. (a) What are the smallest and the largest positive numbers that can be stored in single precision? (b) What is the smallest value of the mantissa that can be stored?Q1 If you know that Z = 4 + 2i and X = -2 = -2V3 – 6i Perform the indicated operation and write your answer in polar form. 1. Z+X 2. Z-X 3. Z.X 4. Z/X 13п, Q2 Put the complex number Z = 2e 6' in the "Cartesian" form Z = a + bi where a, b E R. Q3 Put the complex number Z = 18 + 26i in the "polar" form Z = rej® where r, 0 ER and both r and 0 are positive. Q4 Find a cube root of the number Z = 18 + 26i and put this cube root "Cartesian" form Z a + bi where a, b ER. (Use a calculator and get an exact the value.) Q5 Solve the following second order equations 1. 2x2 – 2ix - 5 = 0 2. x2 – 2x + 5 = 0 Q6 Write the polar form rele for the following complex numbers. Then give your answer in Cartesian form Z = a + bị 1. (1+ v3i) 2. (VZ – vZi) 3. (V3 - i)*00