Normal distribution and Standard normalQuestion 1.Given a normal distribution with u = 87 and o = 3.8, find%3D(a) the normal curve area (probability) for x <=91.2(b) the normal curve area (probability) for x >=78.4(c) the normal curve area (probability) between x = 85.2 and x = 88(d) the normal curve area (probability) between x = 76.6 and x = 90.4

Given X is normal Distributed with mean µ = 87.0 and standard deviation σ = 3.8 now will using…

Answered: Normal distribution and Standard normal…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant criteria? Temperature (°F) 50-54 55-59 60-64 65-69 70-74 75-79 80-84 Frequency 2 NOSHT61 0 5 14 7 Does the frequency distribution appear to have a normal distribution? A. No, the frequencies do not decrease from the maximum frequency to a low frequency. OB. No, the distribution does not appear to be normal. OC. Yes, all the requirements are met.
The test scores for the analytical writing section of a particular standardized test can be approximated by a normal distribution, as shown in the figure. H3.7 (a) What is the maximum score that can be in the bottom 5% of scores? (b) Between what two values does the middle 90% of scores lie? o=0.77 3.7 Score 1.4 (a) The maximum score that can be in the bottom 5% is (Round to two decimal places as needed) (b) The middle 90% of scores lies between (Round to two decimal places as needed.) on the low end and on the high end.
normal distribution
Photon is a training device that is designed to improve a user's reaction time. Similar devices have been criticized for being too easy to master, but the makers of Photon say that their device is built to give most users room to improve. The makers say that even among professional athletes, the proportion, p, who can score the top ranking of "light speed" is less than 18%. A random sample of 115 professional athletes is chosen, and 15 score a ranking of "light speed" while using the device. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to support the claim that the proportion of all professional athletes who can score a ranking of "light speed" is less than 18%. (a) State the null hypothesis H, and the alternative hypothesis H, that you would use for the test. Oロ H: ロ=ロローロ (b) For your hypothesis test, you will use a Z-test. Find the values of np and n (1-p) to confirm that a Z-test can be used. (One…
The test scores for the analytical writing section of a particular standardized test can be approximated by a normal distribution, as shown in the figure. (a) What is the maximum score that can be in the bottom 10% of scores? (b) Between what two values does the middle 80% of scores lie? (a) The maximum score that can be in the bottom 10% is (Round to two decimal places as needed.) H 3.3 Je o=0.76 0.6 3.3 Score -co
(a) The graph shows a Standard Normal Distribution. You are given 1 or 2 z-score(s) and need to shade the area (=probability) corresponding to: P(z > 1.2). Click on the "Shade" menu to select the shading option corresponding to the question [to the left, to the right, or between 2 values]. Then slide the arrow to the appropriate z-score. Shade: Left of a value Click and drag the arrows to adjust the values. -4 -3 -2 -1 2 4 -1.5 (b) Part 2: you are given an area (=probability), and you need to compute c, which is the z-score that corresponds to the statement: P( - c < z < c) (This is an inverse standard normal distribution problem. Use technology to compute c) The arrow can only be dragged to tick marks that are multiples of 0.1 So, round c to 1 decimal place, and then move the arrow to that rounded value. Click on the "Shade" menu to select the shading option corresponding to the question [to the left, to the right, or between 2 values]. (If the question is less c, choose Left of a…

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