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Nonlinear Spring -mmm x(t) 1 kg f(t) = Represent the translational mechanical system shown above in state space about the equilibrium displacement xo √5. The spring is nonlinear, where the relationship between the spring force fs, and the spring displacement, x, is fs = 2x². The applied force is f (t) = 10 + 8f (t), where Sf (t) is a small force about the 10 N constant value. Assume the output to be the displacement of the mass, x(t).

Nonlinear Spring -mmm x(t) 1 kg f(t) = Represent the translational mechanical system shown above in state space about the equilibrium displacement xo √5. The spring is nonlinear, where the relationship between the spring force fs, and the spring displacement, x, is fs = 2x². The applied force is f (t) = 10 + 8f (t), where Sf (t) is a small force about the 10 N constant value. Assume the output to be the displacement of the mass, x(t).

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Nonlinear x(t) Spring -m 1 kg f(t) Represent the translational mechanical system shown above in state space about the equilibrium displacement xo = √5. The spring is nonlinear, where the relationship between the spring force fs, and the spring displacement, x, is fs The applied force is f(t) 10+ Sf (t), where 8f (t) is a small force about the 10 N constant value. Assume the output to be the displacement of the mass, x(t). = = 2x².
Transcribed Image Text:Nonlinear x(t) Spring -m 1 kg f(t) Represent the translational mechanical system shown above in state space about the equilibrium displacement xo = √5. The spring is nonlinear, where the relationship between the spring force fs, and the spring displacement, x, is fs The applied force is f(t) 10+ Sf (t), where 8f (t) is a small force about the 10 N constant value. Assume the output to be the displacement of the mass, x(t). = = 2x².
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