NO3(aq)+ 4 H (aq) + 3eWrite a balancedequation for thehalf-reaction thathappens at thecathode.swer the following questions about this cell.Write a balancedequation for thehalf-reaction thathappens at theanode.Br₂(1)+2e - 2 Br (aq)Write a balancedequation for theoverall reactionthat powers thecell. Be sure thereaction isspontaneous aswritten.Do you haveenoughhalf-reactioninformation tocalculate the cellvoltage understandardconditions?If you said it waspossible tocalculate the cellvoltage, do so andenter your answer- NO(g) + 2 H₂O(1)Br₂ (1) + 2e¯¯ 2Br (aq)0NO(g) + 2H₂0 (1)YesNostandard reduction potential20'red-0Ered+NO₂ (aq) + 4H (aq) + 3e= +0.96 V== +1.065 V

The half-reaction along with their standard reduction potential values are ----------------------------------The electrode that has more standard reduction potential will act as a cathode and undergo reduction. The electrode that has less reduction potential will act as an anode and undergo oxidation. Since, therefore, oxidation of NO occurs at the anode while reduction of Br2 occurs at the cathode. -------- The equation for the half-reaction at the anode is The balanced equation for the half-reaction at the anode is -------- The equation for the half-reaction at the cathode is The balanced equation for the half-reaction at the cathode is -------- The balanced overall cell reaction is ----------------------------------We have enough information to calculate cell voltage. The cell voltage is ----------------------------------The balanced equation for the half-reaction at the anode is The balanced equation for the half-reaction at the cathode is The overall cell reaction Yes, we have enough information to calculate cell voltage. ******************************