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НО. ОН О 12 K2CO3 PhCHO EtOH, 50 °C 70% НО. но, Ph ОН 9

НО. ОН О 12 K2CO3 PhCHO EtOH, 50 °C 70% НО. но, Ph ОН 9

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Propose a reasonable mechanism

 

The image depicts a chemical reaction involving organic compounds. The starting material is compound 12, which undergoes a transformation to produce compound 9. The reaction conditions include the use of potassium carbonate (K₂CO₃), benzaldehyde (PhCHO), ethanol (EtOH) as the solvent, and a temperature of 50°C. The reaction has a yield of 70%. On the left side of the reaction, compound 12 contains a phenyl group, a hydroxy group, and a lactone structure. On the right side, compound 9 has an additional hydroxy group and a phenyl group attached to the central carbon, indicating a nucleophilic addition reaction. The phenyl group is highlighted in red for emphasis on both structures. The arrow in the center indicates the conversion from compound 12 to compound 9, with the specified conditions written above and below the arrow.
Transcribed Image Text:The image depicts a chemical reaction involving organic compounds. The starting material is compound 12, which undergoes a transformation to produce compound 9. The reaction conditions include the use of potassium carbonate (K₂CO₃), benzaldehyde (PhCHO), ethanol (EtOH) as the solvent, and a temperature of 50°C. The reaction has a yield of 70%. On the left side of the reaction, compound 12 contains a phenyl group, a hydroxy group, and a lactone structure. On the right side, compound 9 has an additional hydroxy group and a phenyl group attached to the central carbon, indicating a nucleophilic addition reaction. The phenyl group is highlighted in red for emphasis on both structures. The arrow in the center indicates the conversion from compound 12 to compound 9, with the specified conditions written above and below the arrow.
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