No. 2. X = principal root of no. 1; Y = second root of no. 1; and Z= third root of no. 1 Let: 13-j7 (3 + j4)3 (Y – ji). (4/3) + In² In(jn) – j4(X + j7)n(-4) loge 3-j5 (4 + jZ)e 4 +
No. 2. X = principal root of no. 1; Y = second root of no. 1; and Z= third root of no. 1 Let: 13-j7 (3 + j4)3 (Y – ji). (4/3) + In² In(jn) – j4(X + j7)n(-4) loge 3-j5 (4 + jZ)e 4 +
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![No. 2.
X = principal root of no. 1;
Y = second root of no. 1; and
Z = third root of no. 1
Let:
loge 3-j5
13-j7
(3 + j4)³
(Y – j') ]
(4/3) + In? In(jn) – j4(X + j7)m
.3n
(4 + jZ)eT+
I =
In(-4)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F71920d2f-2825-4695-a82a-376abf38ee3d%2F7184ed7a-a139-45f3-abe5-f9ef95463e0a%2Fr0au4c9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:No. 2.
X = principal root of no. 1;
Y = second root of no. 1; and
Z = third root of no. 1
Let:
loge 3-j5
13-j7
(3 + j4)³
(Y – j') ]
(4/3) + In? In(jn) – j4(X + j7)m
.3n
(4 + jZ)eT+
I =
In(-4)
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