Chapter2: Functions And Their Graphs
Section2.4: A Library Of Parent Functions
Problem 47E: During a nine-hour snowstorm, it snows at a rate of 1 inch per hour for the first 2 hours, at a rate...
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![### Finding the Exact Length of a Curve
#### Problem Statement:
No calculators. Find the exact length of the curve given by:
\[ y = 2 + 2x^{3/2}, \quad 0 \leq x \leq 1 \]
#### Instructions:
To find the length of the curve described by the function \( y = 2 + 2x^{3/2} \) over the interval \([0, 1]\), you can use the arc length formula for a curve in Cartesian coordinates.
The arc length \( L \) of a function \( y = f(x) \) from \( x = a \) to \( x = b \) is given by:
\[ L = \int_{a}^{b} \sqrt{1 + \left( \frac{dy}{dx} \right)^2 } \, dx \]
1. **Compute the derivative** \( \frac{dy}{dx} \):
\[ y = 2 + 2x^{3/2} \]
\[ \frac{dy}{dx} = \frac{d}{dx} \left( 2 + 2x^{3/2} \right) \]
\[ \frac{dy}{dx} = 0 + 2 \cdot \frac{3}{2}x^{1/2} \]
\[ \frac{dy}{dx} = 3x^{1/2} \]
2. **Substitute** \( \frac{dy}{dx} \) into the arc length formula:
\[ L = \int_{0}^{1} \sqrt{1 + \left( 3x^{1/2} \right)^2 } \, dx \]
\[ L = \int_{0}^{1} \sqrt{1 + 9x} \, dx \]
3. **Evaluate the integral**:
To evaluate this integral, one way is to use a trigonometric substitution or a standard integration technique.
Let's proceed with the integration:
\[ L = \int_{0}^{1} \sqrt{1 + 9x} \, dx \]
For simplicity, one can perform this in detail using proper integration methods. However, the primary steps have been outlined to provide insight into the process.
This process will yield the exact length of the given curve from \( x = 0 \) to \( x = 1 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2e042ae-8c1a-4cae-92ef-f152732755cf%2F68ab8aa2-7a05-4cf8-b7a4-122cea9c5fe2%2Fqkxtfbb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Finding the Exact Length of a Curve
#### Problem Statement:
No calculators. Find the exact length of the curve given by:
\[ y = 2 + 2x^{3/2}, \quad 0 \leq x \leq 1 \]
#### Instructions:
To find the length of the curve described by the function \( y = 2 + 2x^{3/2} \) over the interval \([0, 1]\), you can use the arc length formula for a curve in Cartesian coordinates.
The arc length \( L \) of a function \( y = f(x) \) from \( x = a \) to \( x = b \) is given by:
\[ L = \int_{a}^{b} \sqrt{1 + \left( \frac{dy}{dx} \right)^2 } \, dx \]
1. **Compute the derivative** \( \frac{dy}{dx} \):
\[ y = 2 + 2x^{3/2} \]
\[ \frac{dy}{dx} = \frac{d}{dx} \left( 2 + 2x^{3/2} \right) \]
\[ \frac{dy}{dx} = 0 + 2 \cdot \frac{3}{2}x^{1/2} \]
\[ \frac{dy}{dx} = 3x^{1/2} \]
2. **Substitute** \( \frac{dy}{dx} \) into the arc length formula:
\[ L = \int_{0}^{1} \sqrt{1 + \left( 3x^{1/2} \right)^2 } \, dx \]
\[ L = \int_{0}^{1} \sqrt{1 + 9x} \, dx \]
3. **Evaluate the integral**:
To evaluate this integral, one way is to use a trigonometric substitution or a standard integration technique.
Let's proceed with the integration:
\[ L = \int_{0}^{1} \sqrt{1 + 9x} \, dx \]
For simplicity, one can perform this in detail using proper integration methods. However, the primary steps have been outlined to provide insight into the process.
This process will yield the exact length of the given curve from \( x = 0 \) to \( x = 1 \).
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