nn+1 TU En=1 6n in=:

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Determine if the following series converges or diverges. 

The image displays a mathematical series expression:

\[
\sum_{n=1}^{\infty} \frac{\pi^{n+1}}{6^n}
\]

This represents an infinite series where the sum is taken from \( n = 1 \) to infinity. Each term in the series is given by the formula \(\frac{\pi^{n+1}}{6^n}\), with \(\pi\) raised to the power of \(n+1\) in the numerator and \(6^n\) in the denominator. The sigma (\(\sum\)) symbol denotes the summation of all such terms starting from \(n = 1\) to infinity. This concept is commonly used in calculus and analysis for evaluating infinite series.
Transcribed Image Text:The image displays a mathematical series expression: \[ \sum_{n=1}^{\infty} \frac{\pi^{n+1}}{6^n} \] This represents an infinite series where the sum is taken from \( n = 1 \) to infinity. Each term in the series is given by the formula \(\frac{\pi^{n+1}}{6^n}\), with \(\pi\) raised to the power of \(n+1\) in the numerator and \(6^n\) in the denominator. The sigma (\(\sum\)) symbol denotes the summation of all such terms starting from \(n = 1\) to infinity. This concept is commonly used in calculus and analysis for evaluating infinite series.
The image shows a mathematical expression representing an infinite series. The expression is:

\[
\sum_{n=1}^{\infty} \frac{1+n}{3n+1}
\]

This denotes the sum of the series, starting from \( n = 1 \) to infinity, of the fraction \(\frac{1+n}{3n+1}\). Each term in the series is a fraction where the numerator is \( 1+n \) and the denominator is \( 3n+1 \).
Transcribed Image Text:The image shows a mathematical expression representing an infinite series. The expression is: \[ \sum_{n=1}^{\infty} \frac{1+n}{3n+1} \] This denotes the sum of the series, starting from \( n = 1 \) to infinity, of the fraction \(\frac{1+n}{3n+1}\). Each term in the series is a fraction where the numerator is \( 1+n \) and the denominator is \( 3n+1 \).
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