Nitrous acid, HNO₂, can be made by reacting N₂O3 with water as depicted below in a balanced chemical equation: N₂O3 + H₂O → 2HNO₂ If 20.0 grams of N₂O3 were reacted with an excess of water and only 19.5 grams of HNO₂ actually formed, what would be the percent yield of this reaction? Molar Mass of N₂O3 = 76.01 g/mole Molar Mass HNO₂ = 47.013 g/mole Note: Give your answer in percentage, not fraction, form (e.g if it were 25.4%, enter 25.4, NOT 0.254) PLEASE CLEARLY SHOW YOUR WORK FOR THIS AND SUBMIT IT

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Nitrous acid, HNO₂, can be made by reacting N₂O3 with water as depicted below in a balanced
chemical equation:
N₂O3 + H₂O → 2HNO2
If 20.0 grams of N₂O3 were reacted with an excess of water and only 19.5 grams of HNO₂ actually
formed, what would be the percent yield of this reaction?
Molar Mass of N₂O3 = 76.01 g/mole
Molar Mass HNO2 = 47.013 g/mole
Note: Give your answer in percentage, not fraction, form (e.g if it were 25.4%, enter 25.4, NOT
0.254)
PLEASE CLEARLY SHOW YOUR WORK FOR THIS AND SUBMIT IT
Transcribed Image Text:Nitrous acid, HNO₂, can be made by reacting N₂O3 with water as depicted below in a balanced chemical equation: N₂O3 + H₂O → 2HNO2 If 20.0 grams of N₂O3 were reacted with an excess of water and only 19.5 grams of HNO₂ actually formed, what would be the percent yield of this reaction? Molar Mass of N₂O3 = 76.01 g/mole Molar Mass HNO2 = 47.013 g/mole Note: Give your answer in percentage, not fraction, form (e.g if it were 25.4%, enter 25.4, NOT 0.254) PLEASE CLEARLY SHOW YOUR WORK FOR THIS AND SUBMIT IT
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