Nitrogen undergoes an adiabatic process, the pressure volume relationship given as p = (5/V)+1.5 where is in bar and V is in m³. During the process the volume changes from 1.5 x 10° mm3 to 0.05 m3 and the system takes 45 kJ of heat. Determine (i) Work done (i) Work done (ii) Change in internal energy (iii) Final pressure of the gas, if the initial pressure is 1 bar (iv) Final temperature of gas, if the initial temperature is 80°C (v) mass (vi) Change in enthalpy.
Nitrogen undergoes an adiabatic process, the pressure volume relationship given as p = (5/V)+1.5 where is in bar and V is in m³. During the process the volume changes from 1.5 x 10° mm3 to 0.05 m3 and the system takes 45 kJ of heat. Determine (i) Work done (i) Work done (ii) Change in internal energy (iii) Final pressure of the gas, if the initial pressure is 1 bar (iv) Final temperature of gas, if the initial temperature is 80°C (v) mass (vi) Change in enthalpy.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![Nitrogen undergoes an adiabatic process, the pressure volume relationship given as p = (5/V)+1.5 where is in bar and V is in m³. During
the process the volume changes from 1.5 x 108 mm3 to 0.05 m³ and the system takes 45 kJ of heat. Determine (i) Work done (i) Work
done (ii) Change in internal energy (iii) Final pressure of the gas, if the initial pressure is 1 bar (iv) Final temperature of gas, if the initial
temperature is 80°C (v) mass (vi) Change in enthalpy.
Gas
Molecular
weight
(М)
(kJ/kg K)
(kJ/kg K)
Air
28.97
1.005
0.718
Oxygen
Nitrogen
Hydrogen
Carbon monoxide
32
0.920
0.660
28
1.046
0.754
2
14.40
10.40
28
1.046
0.754](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffcec74a6-8d36-4d64-951a-a28ac1ab6797%2Fabb0f83b-eb45-466a-918e-3dcb6dc79e6f%2Ff6fzaxz_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Nitrogen undergoes an adiabatic process, the pressure volume relationship given as p = (5/V)+1.5 where is in bar and V is in m³. During
the process the volume changes from 1.5 x 108 mm3 to 0.05 m³ and the system takes 45 kJ of heat. Determine (i) Work done (i) Work
done (ii) Change in internal energy (iii) Final pressure of the gas, if the initial pressure is 1 bar (iv) Final temperature of gas, if the initial
temperature is 80°C (v) mass (vi) Change in enthalpy.
Gas
Molecular
weight
(М)
(kJ/kg K)
(kJ/kg K)
Air
28.97
1.005
0.718
Oxygen
Nitrogen
Hydrogen
Carbon monoxide
32
0.920
0.660
28
1.046
0.754
2
14.40
10.40
28
1.046
0.754
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