Nitrogen monoxide, NO, reacts with hydrogen to give nitrous oxide, N20, and water. 2NO(9) + H2 (9) → N,0(g) + H2O(9) In a series of experiments, the following initial rates of disappearance of NO were obtained: Initial Concentration of NO Initial Concentration of H2 Initial Rate of Reaction of NO Exp. 1 1.3 x 10-3 M 9.5 x 10-3 M 4.6 x 10-6 Ms Exp. 2 2.6 x 10-3 M 9.5 х 10-3 м 1.8 x 10-5 Ms Exp. 3 1.3 x 10-8 M 1.9 x 10-2 M 9.2 x 10-6 Ms a Find the rate law for the reaction of NO. (Use k for the rate constant.) Rate =

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### Reaction Rate Problem

**Problem Overview:**

Nitrogen monoxide, NO, reacts with hydrogen to produce nitrous oxide, \( \text{N}_2\text{O} \), and water. The balanced chemical equation for the reaction is:

\[ 
2\text{NO}(g) + \text{H}_2(g) \rightarrow \text{N}_2\text{O}(g) + \text{H}_2\text{O}(g)
\]

A series of experiments were conducted to determine the initial rates of disappearance of NO under different conditions.

**Experimental Data:**

The table below shows the initial concentrations of NO and \( \text{H}_2 \), and the initial rate of reaction for NO.

| Experiment | Initial Concentration of NO (\(M\)) | Initial Concentration of \( \text{H}_2 \) (\(M\)) | Initial Rate of Reaction of NO (\(M/s\)) |
|------------|------------------------------------|---------------------------------------------|---------------------------------------|
| Exp. 1     | \(1.3 \times 10^{-3}\)             | \(9.5 \times 10^{-3}\)                       | \(4.6 \times 10^{-6}\)                |
| Exp. 2     | \(2.6 \times 10^{-3}\)             | \(9.5 \times 10^{-3}\)                       | \(1.8 \times 10^{-5}\)                |
| Exp. 3     | \(1.3 \times 10^{-3}\)             | \(1.9 \times 10^{-2}\)                       | \(9.2 \times 10^{-6}\)                |

**Task:**

- **a.** Find the rate law for the reaction of NO.

Use \( k \) for the rate constant.

**Equation to Solve:**

Rate = \(\_\_\_\_\_\_\)
Transcribed Image Text:### Reaction Rate Problem **Problem Overview:** Nitrogen monoxide, NO, reacts with hydrogen to produce nitrous oxide, \( \text{N}_2\text{O} \), and water. The balanced chemical equation for the reaction is: \[ 2\text{NO}(g) + \text{H}_2(g) \rightarrow \text{N}_2\text{O}(g) + \text{H}_2\text{O}(g) \] A series of experiments were conducted to determine the initial rates of disappearance of NO under different conditions. **Experimental Data:** The table below shows the initial concentrations of NO and \( \text{H}_2 \), and the initial rate of reaction for NO. | Experiment | Initial Concentration of NO (\(M\)) | Initial Concentration of \( \text{H}_2 \) (\(M\)) | Initial Rate of Reaction of NO (\(M/s\)) | |------------|------------------------------------|---------------------------------------------|---------------------------------------| | Exp. 1 | \(1.3 \times 10^{-3}\) | \(9.5 \times 10^{-3}\) | \(4.6 \times 10^{-6}\) | | Exp. 2 | \(2.6 \times 10^{-3}\) | \(9.5 \times 10^{-3}\) | \(1.8 \times 10^{-5}\) | | Exp. 3 | \(1.3 \times 10^{-3}\) | \(1.9 \times 10^{-2}\) | \(9.2 \times 10^{-6}\) | **Task:** - **a.** Find the rate law for the reaction of NO. Use \( k \) for the rate constant. **Equation to Solve:** Rate = \(\_\_\_\_\_\_\)
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