Draw and label the P-V and T-S diagram properly. Nitrogen gas at 90° F (MW=28) goes through a compressor,increasing its pressure from 10 psi to 65 psi. The temperatureremained constant throughout. Determine the work in Hp fora steady flow process; AKE=0, APE=0; mass flow rate ofnitrogen is 2 Ibm/min.

Answered: Nitrogen gas at 90° F (MW=28) goes…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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Question

Draw and label the P-V and T-S diagram properly.

Nitrogen gas at 90° F (MW=28) goes through a compressor,
increasing its pressure from 10 psi to 65 psi. The temperature
remained constant throughout. Determine the work in Hp for
a steady flow process; AKE=0, APE=0; mass flow rate of
nitrogen is 2 Ibm/min.

Expert Solution

Step 1

First law of thermodynamics stated as energy neither can be created nor be destroyed, it can only transform one form of energy to another. Total energy of the universe is constant.

The mathematical form can be written as,

$q + w = U w h e r e, q = a m o u n t o f h e a t a d d e d t o t h e s y s t e m f r o m s u r r o u n d i n g s w = a m o u n t o f w r k d o n e b y t h e s y s t e m U = i n t e r n a l e n e r g y o f t h e s y s t e m$

Now the differential form of first law of thermodynamics is written as,

$d q + d w = d U . . . . . . . . . . . . . . . . . . . (1)$

Now for an isothermal reversible process work done is calculated as

$d w = - P d V, w h e r e, P - V w o r k i s c o n s i d e r e d, P = p r e s s u r e, V = v o l u m e S o, w = \int - P d V . . . . . . . . . . . . (2)$

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