Nitrogen dioxide will react to form nitrogen monoxide and oxygen gas according to the equation: 2NO2(g) → 2NO(g)+O2(g) A reaction container starts with an initial NO,(g) concentration of 0.350 M. What is the concentration of NO2(g) after the reactions processed for 30 seconds given the rate of NO;(g) loss 1.20× 10-3 M/s?
Nitrogen dioxide will react to form nitrogen monoxide and oxygen gas according to the equation: 2NO2(g) → 2NO(g)+O2(g) A reaction container starts with an initial NO,(g) concentration of 0.350 M. What is the concentration of NO2(g) after the reactions processed for 30 seconds given the rate of NO;(g) loss 1.20× 10-3 M/s?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Chemical Reaction of Nitrogen Dioxide**
In this example, nitrogen dioxide (NO₂) reacts to form nitrogen monoxide (NO) and oxygen gas (O₂). The chemical equation representing the reaction is:
\[ 2NO_2(g) \rightarrow 2NO(g) + O_2(g) \]
**Problem Statement:**
A reaction container starts with an initial concentration of nitrogen dioxide, NO₂(g), at 0.350 M (molarity). The task is to determine the concentration of NO₂(g) after the reaction has proceeded for 30 seconds, given that the rate of NO₂(g) loss is \(1.20 \times 10^{-3}\) M/s.
**Calculation Summary:**
Given:
- Initial concentration of NO₂(g): 0.350 M
- Rate of reaction: \(1.20 \times 10^{-3}\) M/s
- Reaction time: 30 seconds
The rate of reaction indicates how fast NO₂ is being consumed. To find the concentration after 30 seconds:
\[ \text{Change in concentration} = \text{Rate} \times \text{Time} = 1.20 \times 10^{-3} \times 30 \]
\[ \text{Change in concentration} = 0.036 \, \text{M} \]
Subtract this change from the initial concentration to get the final concentration:
\[ \text{Final concentration of NO}_2(g) = 0.350 \, \text{M} - 0.036 \, \text{M} = 0.314 \, \text{M} \]
The concentration of NO₂(g) after 30 seconds is 0.314 M. This example demonstrates the calculation of reaction kinetics for a given chemical process.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9308dc3b-f957-4c0f-a27d-3b5b651b48dc%2F3956ac3a-3949-4785-a3c7-4449119b2085%2F6kk7ir_processed.png&w=3840&q=75)
Transcribed Image Text:**Chemical Reaction of Nitrogen Dioxide**
In this example, nitrogen dioxide (NO₂) reacts to form nitrogen monoxide (NO) and oxygen gas (O₂). The chemical equation representing the reaction is:
\[ 2NO_2(g) \rightarrow 2NO(g) + O_2(g) \]
**Problem Statement:**
A reaction container starts with an initial concentration of nitrogen dioxide, NO₂(g), at 0.350 M (molarity). The task is to determine the concentration of NO₂(g) after the reaction has proceeded for 30 seconds, given that the rate of NO₂(g) loss is \(1.20 \times 10^{-3}\) M/s.
**Calculation Summary:**
Given:
- Initial concentration of NO₂(g): 0.350 M
- Rate of reaction: \(1.20 \times 10^{-3}\) M/s
- Reaction time: 30 seconds
The rate of reaction indicates how fast NO₂ is being consumed. To find the concentration after 30 seconds:
\[ \text{Change in concentration} = \text{Rate} \times \text{Time} = 1.20 \times 10^{-3} \times 30 \]
\[ \text{Change in concentration} = 0.036 \, \text{M} \]
Subtract this change from the initial concentration to get the final concentration:
\[ \text{Final concentration of NO}_2(g) = 0.350 \, \text{M} - 0.036 \, \text{M} = 0.314 \, \text{M} \]
The concentration of NO₂(g) after 30 seconds is 0.314 M. This example demonstrates the calculation of reaction kinetics for a given chemical process.
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