Nitric oxide gas (NO) reacts with chlorine gas according to the reaction NO + 1/2C12 NOCI The following initial rates of reaction have been measured for the given reagent concentrations. Expt. # Rate (M/hr) NO (M) Cl2 (M) 1 1.19 0.50 0.50 4.79 1.00 0.50 9.59 1.00 1.00 Which of the following is the rate law (rate equation) for this reaction? Select one: O a. rate = k[NO]?[CI2] O b. rate k[NO] Oc. rate = K[NO][Cl2]2 O d. rate = k[NO][Cl] O e. rate = k[NO] [CIl,]? %3D

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### Reaction of Nitric Oxide Gas with Chlorine Gas

Nitric oxide gas (NO) reacts with chlorine gas according to the following chemical reaction:

\[ \text{NO} + \frac{1}{2}\text{Cl}_2 \rightarrow \text{NOCl} \]

Below are the measured initial rates of reaction for the given reagent concentrations:

| Expt. # | Rate (M/hr) | NO (M) | Cl<sub>2</sub> (M) |
|---------|-------------|--------|-------------------|
| 1       | 1.19        | 0.50   | 0.50              |
| 2       | 4.79        | 1.00   | 0.50              |
| 3       | 9.59        | 1.00   | 1.00              |

### Question

Which of the following is the rate law (rate equation) for this reaction?

Select one:

a. rate = \( k[\text{NO}]^2[\text{Cl}_2] \)

b. rate = \( k[\text{NO}] \)

c. rate = \( k[\text{NO}][\text{Cl}_2]^{1/2} \)

d. rate = \( k[\text{NO}][\text{Cl}_2] \)

e. rate = \( k[\text{NO}]^2[\text{Cl}_2]^2 \)

### Detailed Explanation of Experimental Data

1. **Experiment 1:**
   - Rate = 1.19 M/hr
   - [NO] = 0.50 M
   - [Cl<sub>2</sub>] = 0.50 M

2. **Experiment 2:**
   - Rate = 4.79 M/hr
   - [NO] = 1.00 M
   - [Cl<sub>2</sub>] = 0.50 M

3. **Experiment 3:**
   - Rate = 9.59 M/hr
   - [NO] = 1.00 M
   - [Cl<sub>2</sub>] = 1.00 M

### Analysis of the Rate Data

- Between Experiments 1 and 2, the concentration of NO is doubled (from 0.50 M to 1.00 M)
Transcribed Image Text:### Reaction of Nitric Oxide Gas with Chlorine Gas Nitric oxide gas (NO) reacts with chlorine gas according to the following chemical reaction: \[ \text{NO} + \frac{1}{2}\text{Cl}_2 \rightarrow \text{NOCl} \] Below are the measured initial rates of reaction for the given reagent concentrations: | Expt. # | Rate (M/hr) | NO (M) | Cl<sub>2</sub> (M) | |---------|-------------|--------|-------------------| | 1 | 1.19 | 0.50 | 0.50 | | 2 | 4.79 | 1.00 | 0.50 | | 3 | 9.59 | 1.00 | 1.00 | ### Question Which of the following is the rate law (rate equation) for this reaction? Select one: a. rate = \( k[\text{NO}]^2[\text{Cl}_2] \) b. rate = \( k[\text{NO}] \) c. rate = \( k[\text{NO}][\text{Cl}_2]^{1/2} \) d. rate = \( k[\text{NO}][\text{Cl}_2] \) e. rate = \( k[\text{NO}]^2[\text{Cl}_2]^2 \) ### Detailed Explanation of Experimental Data 1. **Experiment 1:** - Rate = 1.19 M/hr - [NO] = 0.50 M - [Cl<sub>2</sub>] = 0.50 M 2. **Experiment 2:** - Rate = 4.79 M/hr - [NO] = 1.00 M - [Cl<sub>2</sub>] = 0.50 M 3. **Experiment 3:** - Rate = 9.59 M/hr - [NO] = 1.00 M - [Cl<sub>2</sub>] = 1.00 M ### Analysis of the Rate Data - Between Experiments 1 and 2, the concentration of NO is doubled (from 0.50 M to 1.00 M)
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