nitial Pro Final volume (V₂) Initial temperature Initial volume (V₁) = 234 Initial temperature (1₁) = 200K Use the combined gas law to solve the following problems: 8) If I initially have a gas at a pressure if 12 atm, a volume of 23 liters, and a temperature of 200.0 K, and then I raise the pressure to 14 atm and increase the temperature to 300.0 K, what is the new volume of the P, Vi Pa Va gas? V₂ = Pivita T₁. Pa 12 atm x 23LX3000K T₁ 30. L Pressure (Pa): 1 Yatm 5713557 Piv, Ta

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Can you help me with the number 8 question? Can you explain step by step formula for the combined gas law? Can you put the formula to plug in the fraction to give the correct answer to the formula?
**Educational Resource: Solving Gas Law Problems**

---

**Topic: Combined and Ideal Gas Laws**

This resource provides detailed solutions to a series of gas law problems using both the combined gas law and the ideal gas law. The following examples illustrate the application of these laws:

### Example Problems:

1. **Combined Gas Law**
   - **Problem 8**: Initial and final conditions of a gas are given, and the task is to find the new volume after pressure and temperature changes.
     - **Given:**
       - Initial Pressure (P₁): 12 atm
       - Initial Volume (V₁): 23 L
       - Initial Temperature (T₁): 200.0 K
       - Final Pressure (P₂): 14 atm
       - Final Temperature (T₂): 300.0 K
     - **Solution:**
       - V₂ = \((P₁ \times V₁ \times T₂) / (P₂ \times T₁)\)
       - Calculated V₂: 30 L

2. **Ideal Gas Law**
   - **Problem 10**: Calculate the pressure exerted by a gas.
     - **a.** For 250 L of gas containing 8.5 moles at 320 K.
       - Use \(PV = nRT\)
       - R (Gas Constant): \(0.0821 \, \text{L atm/mol K}\)
       - Pressure (P): 0.14 atm

     - **b.** For 4.75 L of gas containing 0.86 moles at 300 K.
       - Pressure (P): 4.45 atm

   - **Problem 11**: Calculate the volume of gases at given conditions.
     - **a.** For 2.00 moles of H₂ at 300 K and 1.25 atm.
       - Volume (V): 39.4 L

     - **b.** For 0.425 moles of NH₃ at 0.724 atm and 37°C.
       - Volume (V): 14.9 L

3. **Mole Determination Using Ideal Gas Law**
   - **Problem 12**: Determine the number of moles in given gas systems.
     - **a.** For 1.25 L of O₂ at 1.06 atm and
Transcribed Image Text:**Educational Resource: Solving Gas Law Problems** --- **Topic: Combined and Ideal Gas Laws** This resource provides detailed solutions to a series of gas law problems using both the combined gas law and the ideal gas law. The following examples illustrate the application of these laws: ### Example Problems: 1. **Combined Gas Law** - **Problem 8**: Initial and final conditions of a gas are given, and the task is to find the new volume after pressure and temperature changes. - **Given:** - Initial Pressure (P₁): 12 atm - Initial Volume (V₁): 23 L - Initial Temperature (T₁): 200.0 K - Final Pressure (P₂): 14 atm - Final Temperature (T₂): 300.0 K - **Solution:** - V₂ = \((P₁ \times V₁ \times T₂) / (P₂ \times T₁)\) - Calculated V₂: 30 L 2. **Ideal Gas Law** - **Problem 10**: Calculate the pressure exerted by a gas. - **a.** For 250 L of gas containing 8.5 moles at 320 K. - Use \(PV = nRT\) - R (Gas Constant): \(0.0821 \, \text{L atm/mol K}\) - Pressure (P): 0.14 atm - **b.** For 4.75 L of gas containing 0.86 moles at 300 K. - Pressure (P): 4.45 atm - **Problem 11**: Calculate the volume of gases at given conditions. - **a.** For 2.00 moles of H₂ at 300 K and 1.25 atm. - Volume (V): 39.4 L - **b.** For 0.425 moles of NH₃ at 0.724 atm and 37°C. - Volume (V): 14.9 L 3. **Mole Determination Using Ideal Gas Law** - **Problem 12**: Determine the number of moles in given gas systems. - **a.** For 1.25 L of O₂ at 1.06 atm and
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