Nichrome wire of cross- sectional radius 0.545 mm is to be used in winding a heating coil. If the coil must carry a current of 6.30 A when a voltage of 120 V is applied across its ends, find (a) the required resistance of the coil. (b) the length of wire you must use to wind the coil.  Note: For Nichrome, the resistivity, ρ, is 150x10-8 Ω·m.

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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Nichrome wire of cross- sectional radius 0.545 mm is to be used in winding a heating coil. If the coil must carry a current of 6.30 A when a voltage of 120 V is applied across its ends, find (a) the required resistance of the coil. (b) the length of wire you must use to wind the coil. 

Note: For Nichrome, the resistivity, ρ, is 150x10-8 Ω·m.

Expert Solution
Step 1

Given data 

The radius is r=0.545 mm

The current is Io=6.30 A

The voltage is Vo=120 V

The resistivity is ρ=150×10-8 Ωm 

(a)

The resistance is,

Ro=VoIo=120 V6.30 A=19.04 Ω

Thus, the resistance is 19.04 Ω

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