NH,* Glycine = CH,-c00- I liter of 0.1 M glycine. pKa's = 2.34 and 9.6 c. How much 5M KOH is needed to change pH from 9 to 10 for 1 Liter of 0.1M glycine? pH = pka + log A/HA 10 = 9.6 + log A/HA so: log A/HA = 0.4 thus A/HA = 2.5 → 2.5HA = A HA + A = 0.1 M → HA + 2.5 HA = 0.1 M → 3.5HA= 0.1M so HA at pH 10 = 0.029 males/L from pH 9 HA is converted to A by adding OH", that is HA is lowered from 0.08M to 0.029M or a change of 0.051 moles 0.051 moles/5 moles/L = 0.01 L → 10 ml of 5M KOH %3D

NH,* Glycine = CH,-c00- I liter of 0.1 M glycine. pKa's = 2.34 and 9.6 c. How much 5M KOH is needed to change pH from 9 to 10 for 1 Liter of 0.1M glycine? pH = pka + log A/HA 10 = 9.6 + log A/HA so: log A/HA = 0.4 thus A/HA = 2.5 → 2.5HA = A HA + A = 0.1 M → HA + 2.5 HA = 0.1 M → 3.5HA= 0.1M so HA at pH 10 = 0.029 males/L from pH 9 HA is converted to A by adding OH", that is HA is lowered from 0.08M to 0.029M or a change of 0.051 moles 0.051 moles/5 moles/L = 0.01 L → 10 ml of 5M KOH %3D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Choose the buffer with the greatest buffering capacity: d. 0.25M formic acid/formate buffer at pH 3, pKa 3.75 b. 0.25M HEPESH+/HEPES buffer at pH 10, pKa = 8.08 c. 0.75M acetic acid/acetate buffer at pH 4.76, pKa = 4.76 a. 1M acetic acid/acetate buffer at pH 4.76, pKa = 4.76 Next Page