ng at a constant 10.1 m/s when a 45 N force starts to act in the opposite direction stopping the object after it has traveled. How

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Chapter1: Units, Trigonometry. And Vectors
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a mass of 8 kg is traveling at a constant 10.1 m/s when a 45 N force starts to act in the opposite direction stopping the object after it has traveled. How much work was done by the force in stopping the object?

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Step 1

We know that the mass m = 8 kg traveling with the constant velocity of v = 10.1 m/s, and a force of F = 45 N is applied to stop the motion in the opposite direction of the motion. 

We know that  newton second law 

 F=ma  -------------- eq1 

a is the acceleration 

We also know that  the third equation of motion is given as 

v2=u2+2as   -------------- eq2 

where v is the final velocity 

u is the initial velocity and a is the acceleration 

s is the distance travel 

 

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