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NG 2. Molality (m) of Unknown Info

NG 2. Molality (m) of Unknown Info

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Try 1: / 0.0611 Moles of water in Unknown 2 2 Info 0.0181 Mass (kg) of acetic acid in Unknown. NOTE: The density of acetic acid is NOT 1.00 g/mL NG 2 Info NG Molality (m) of Unknown Info NG 2 Experimental freezing-point depression constant, k (°C/m) (Assume i=1) Info ER
Transcribed Image Text:Try 1: / 0.0611 Moles of water in Unknown 2 2 Info 0.0181 Mass (kg) of acetic acid in Unknown. NOTE: The density of acetic acid is NOT 1.00 g/mL NG 2 Info NG Molality (m) of Unknown Info NG 2 Experimental freezing-point depression constant, k (°C/m) (Assume i=1) Info ER
LAB DATA Freezing Point (°C) of pure acetic acid 17.0 1.1 Volume (mL) of water in Unknown Volume (mL) of acetic acid in Unknown 17.2 3.8 Freezing point (°C) of Unknown Calculations Try 1: X 17.0 Try 2: / 13.2 Freezing Point Depression (°C) of Unknown 2 Info Trv 1: / 0.0611
Transcribed Image Text:LAB DATA Freezing Point (°C) of pure acetic acid 17.0 1.1 Volume (mL) of water in Unknown Volume (mL) of acetic acid in Unknown 17.2 3.8 Freezing point (°C) of Unknown Calculations Try 1: X 17.0 Try 2: / 13.2 Freezing Point Depression (°C) of Unknown 2 Info Trv 1: / 0.0611
Expert Solution
Step 1

                    Freezing point of pure acetic acid = 17.0oC

                               Freezing point of unknown = 3.8oC

                             Depression in freezing point = (17 - 3.8)

                                                                            = 13.2oC

                             Volume of water in unknown = 1.1 mL

                         Volume of acetic acid unknown = 17.2 mL

                                                 Density of water = 1.00 g/mL

                                 mass of water in unknown = 1.1 g

                                    Molecular mass of water = 18 g/mol

              number of moles of water in unknown = 1.1 g/ 18 g

         number of moles of water in unknown  = 0.061 mol

 

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