Can I have an answer for this two questions? Next you take measurements of different long bones to estimate stature.Humerus length = 30.04 cmFemur length = 42.5 cmTibia length = 33.88 cmYou use the following regression formulas to estimate the stature of the individual. For each estimated stature, round to the nearest .1 decimal place.Humerus regression formula:stature (cm) = (3.08 * humerus length) + 70.45Based on the humerus, the individual is estimated to beFemur regression formula:stature (cm) = (2.38* femur length) + 61.41Based on the femur, the individual is estimated to beTibia regression formula:stature (cm) = (2.52* tibia length) + 78.62Based on the tibia, the individual is estimated to beFollow this link to convert cm to feet and inches.cm.cm.cm.After converting all 3 estimates based on the different long bone regression formulas, the individual was likelyinches tall (round to the nearest inch).feet Luckily the condition of the remains is good enough to get a DNA sample. You send the DNA to your friend who is a population geneticist. The population geneticists decides just to look at themitochondrial DNA (mtDNA) because it is a fast and cheap way to assess possible ancestry.AL AAT AboriginaTawaPHIDAEJP JacaneseAU AMAM AmerindsBU BUNCH CHED EsimeEV CHHA HA CHIES DA DANMT Man Tawerese 38 SemesMZ MAGISINKKD KomYOU KEEMAMAMD MongolsNO No DeneNNVANEuropeAfricaPA heaPE PersisPO PorynesanCong2006.coOohTw ThanYu Tumsuz catersYA anHVbeccscators are shownMTONA Haplogroupsof the WorldPOANOtherMAare tar generarvery large Theates espeAce,and some areasto resent the sivation before the ecen Eurocar con tepening out 1500 KOAssists are somyResults come back that the remains are of an individual with the H mtDNA haplogroup. Based on the reference map above showing the distribution of mtDNA haplogroups from around theworld, the individual likely traces their ancestry back to:O Americas (Native American)OSE Asia

Given that: Humerus length = 30.04 cm Femur length = 42.5 cm Tibia length 33.88 cm = Using humerus regression formula: Stature (cm) = (3.08*humerus length) + 70.45 Or (3.08*30.04) + 70.45 = 163.0 cm Therefore, based on the humerus, the individual is estimated to be 163.0 cm. Using femur regression formula: stature (cm) = (2.38* femur length) + 61.41 Or (2.38*42.5) + 61.41 = 162.6 cm Based on the femur, the individual is estimated to be 162.6 cm. Now, using tibia regression formula: stature (cm) = (2.52*tibia length)+ 78.62 Or (2.52*33.88) + 78.62 = 164.0 cm Based on tibia, the individual is estimated to be 164.0 cmTherefore, based on these formulae, the person is 163 2 cm (average of the above three values) Or 163.2/2.54 inches = 64.25 inches = 5 feet 4¼ inches. Dear student, Due to the poor image quality of the second question, we are unable to read it clearly, Kindly repost the second question. Sorry for the inconveinences. Thank you.