Newton's Second Law Term: Name: +K 10 30°. 1. Consider the situation in the figure above with M = 1 kg, m = Which of the following represents the equation of motion of the hanging block. 0.75 kg, and 0 a. T = ma b. тg — Т %3 та с. тд + T %3 та d. mg = ma %3D 2. What is the equation of motion along the incline for block M? a. T – Mg = Ma b. T – Mg cos 0 = 0 c. T – Mg sin 0 = Ma d. T – Mg sin 0 = 0 - %3D e. T+ Mg cos 0 = 0 3. What is the acceleration of the system? a. 0 m/s? b. 1.4 m/s² с. 4.9 т/s? d. 6.3 m/s² e. 9.8 m/s? 4. In order for the tensions in the string on both sides of the pulley to be equal, the pulley must be a. large b. massless C. small d. frictionless e. both b and d 5. Determine the tension in the string. a. 1.4 N b. 6.3 N c. 8.4 N d. 9.8 N e. 11.2 N plces 0.1 ow do fast will e object d.6m/e lling
Newton's Second Law Term: Name: +K 10 30°. 1. Consider the situation in the figure above with M = 1 kg, m = Which of the following represents the equation of motion of the hanging block. 0.75 kg, and 0 a. T = ma b. тg — Т %3 та с. тд + T %3 та d. mg = ma %3D 2. What is the equation of motion along the incline for block M? a. T – Mg = Ma b. T – Mg cos 0 = 0 c. T – Mg sin 0 = Ma d. T – Mg sin 0 = 0 - %3D e. T+ Mg cos 0 = 0 3. What is the acceleration of the system? a. 0 m/s? b. 1.4 m/s² с. 4.9 т/s? d. 6.3 m/s² e. 9.8 m/s? 4. In order for the tensions in the string on both sides of the pulley to be equal, the pulley must be a. large b. massless C. small d. frictionless e. both b and d 5. Determine the tension in the string. a. 1.4 N b. 6.3 N c. 8.4 N d. 9.8 N e. 11.2 N plces 0.1 ow do fast will e object d.6m/e lling
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:Newton's Second Law
Term:
Name:
+K
10
30°.
1. Consider the situation in the figure above with M = 1 kg, m =
Which of the following represents the equation of motion of the hanging block.
0.75 kg, and 0
a. T = ma
b. тg — Т %3 та
с. тд + T %3 та
d. mg = ma
%3D
2. What is the equation of motion along the incline for block M?
a. T – Mg = Ma
b. T – Mg cos 0 = 0
c. T – Mg sin 0 = Ma
d. T – Mg sin 0 = 0
-
%3D
e. T+ Mg cos 0 = 0
3. What is the acceleration of the system?
a. 0 m/s?
b. 1.4 m/s²
с. 4.9 т/s?
d. 6.3 m/s²
e. 9.8 m/s?

Transcribed Image Text:4. In order for the tensions in the string on both sides of the pulley to be equal, the pulley
must be
a. large
b. massless
C. small
d. frictionless
e. both b and d
5. Determine the tension in the string.
a. 1.4 N
b. 6.3 N
c. 8.4 N
d. 9.8 N
e. 11.2 N
plces
0.1
ow do
fast will e object
d.6m/e
lling
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