Newton's Law of Cooling states that the temperature (T) of an object at any time (1), in minutes, can be described by the equation T= Tg * (To - Tg)e*, where Tg is the temperature of he surrounding environment, Tg is the initial temperature of the object, and k is the cooling rate. What is the cooling rate of an object if the inital temperature was 400* C, the surrounding environment temperature was 30* C, and it took 105 minutes to cool down to 125° C. Round your result to 3 decimal places. Ok=0.011 Ok=0.012 OK=0.013 Ok=0.014
Newton's Law of Cooling states that the temperature (T) of an object at any time (1), in minutes, can be described by the equation T= Tg * (To - Tg)e*, where Tg is the temperature of he surrounding environment, Tg is the initial temperature of the object, and k is the cooling rate. What is the cooling rate of an object if the inital temperature was 400* C, the surrounding environment temperature was 30* C, and it took 105 minutes to cool down to 125° C. Round your result to 3 decimal places. Ok=0.011 Ok=0.012 OK=0.013 Ok=0.014
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![Newton's Law of Cooling states that the temperature (7) of an object at any time (1), in minutes, can be described by the equation T= Ts + (To - Ts)e*, where Ts is the temperature of
the surrounding environment, To is the initial temperature of the object, and k is the cooling rate.
What is the cooling rate of an object if the initial temperature was 400° C, the surrounding environment temperature was 30° C, and it took 105 minutes to cool down to 125° C. Round
your result to 3 decimal places.
k = 0.011
Ok= 0.012
Ok= 0.013
Ok=0.014](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc4fcc531-835e-4e1d-887e-db82b4f310e3%2Fbafef5d5-3765-4aff-95ce-01e24e8c049c%2F11irzir_processed.png&w=3840&q=75)
Transcribed Image Text:Newton's Law of Cooling states that the temperature (7) of an object at any time (1), in minutes, can be described by the equation T= Ts + (To - Ts)e*, where Ts is the temperature of
the surrounding environment, To is the initial temperature of the object, and k is the cooling rate.
What is the cooling rate of an object if the initial temperature was 400° C, the surrounding environment temperature was 30° C, and it took 105 minutes to cool down to 125° C. Round
your result to 3 decimal places.
k = 0.011
Ok= 0.012
Ok= 0.013
Ok=0.014
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