Newton's heating-cooling law states that the rate of change in the temperature, H, is proportional to the difference between the object and the surrounding temperature. Let H(t) be the temperature of the object being heated and S be the surrounding temperature. A cold object at 35 degree is placed in an oven at 350 degrees Fahrenheit and after 30 minutes the object is 100 degrees. Write and solve the differential equation which describes the temperature of the object over time, where time is measured in hours. ○ H(t) = 100 - 315e-0.4622t ○ H(t) = 350 – 100e-0.4622t ○ H(t) = 350 - 315e-0.4622t O H(t) = 100 - 35e- ,-0.4622t
Newton's heating-cooling law states that the rate of change in the temperature, H, is proportional to the difference between the object and the surrounding temperature. Let H(t) be the temperature of the object being heated and S be the surrounding temperature. A cold object at 35 degree is placed in an oven at 350 degrees Fahrenheit and after 30 minutes the object is 100 degrees. Write and solve the differential equation which describes the temperature of the object over time, where time is measured in hours. ○ H(t) = 100 - 315e-0.4622t ○ H(t) = 350 – 100e-0.4622t ○ H(t) = 350 - 315e-0.4622t O H(t) = 100 - 35e- ,-0.4622t
Chapter6: Exponential And Logarithmic Functions
Section: Chapter Questions
Problem 31PT: A bottle of soda with a temperature of 71 Fahrenheit was taken off a shelf and placed ina...
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Transcribed Image Text:Newton's heating-cooling law states that the rate of change in the temperature, H, is proportional to the difference between the object
and the surrounding temperature. Let H(t) be the temperature of the object being heated and S be the surrounding temperature. A
cold object at 35 degree is placed in an oven at 350 degrees Fahrenheit and after 30 minutes the object is 100 degrees.
Write and solve the differential equation which describes the temperature of the object over time, where time is measured in hours.
OH(t) = 100 - 315e-0.4622t
○ H(t) = 350 - 100e-0.4622t
○ H(t) = 350 – 315e-0.4622t
OH(t) = 100 - 35e-0.4622t
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