Network Addresses Using the IP address and subnet mask shown write out the network address: 188. 10.0.0 188.10.18.2 255.255.0.0 10. 10.48.0 10.10.48.80 255.255.255.0 192.149.24.191 255.255.255.0 150.203.23.19 255.255.0.0 10.10.10.10 255.0.0.0 186.13.23.110 255.255.255.0 223.69.230.250 255.255.0.0 200.120.135.15 255.255.255.0 27.125.200 151 255.0.0.0 199.20 150 35 255 255 2550 191 55 165 135 255.255 255.0 28 212 250 254 255 255 0 0

Network Addresses Using the IP address and subnet mask shown write out the network address: 188. 10.0.0 188.10.18.2 255.255.0.0 10. 10.48.0 10.10.48.80 255.255.255.0 192.149.24.191 255.255.255.0 150.203.23.19 255.255.0.0 10.10.10.10 255.0.0.0 186.13.23.110 255.255.255.0 223.69.230.250 255.255.0.0 200.120.135.15 255.255.255.0 27.125.200 151 255.0.0.0 199.20 150 35 255 255 2550 191 55 165 135 255.255 255.0 28 212 250 254 255 255 0 0

Enhanced Discovering Computers 2017 (Shelly Cashman Series) (MindTap Course List)

1st Edition

ISBN:9781305657458

Author:Misty E. Vermaat, Susan L. Sebok, Steven M. Freund, Mark Frydenberg, Jennifer T. Campbell

Publisher:Misty E. Vermaat, Susan L. Sebok, Steven M. Freund, Mark Frydenberg, Jennifer T. Campbell

Chapter10: Communicating Digital Content: Wired And Wireless Networks And Devices

Section: Chapter Questions

Problem 4MC

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Similar questions

Variable Length Subnet Mask Let's say that you are given a network address block as 192.168.16.0/24, and are asked to divide it into five different networks. The largest network will have 80 hosts. What would be the subnet mask for this network? Oa. 255.255.255.0 or / 24 Ob. 255.255.255.252 or /30 O. 255.255.255.128 or/25 Od. 255.255.255.224 or /27
Network Addresses Using the IP address and subnetmask shown write out the network address: 188. 10.0.0 188.10.18.2 255 255.0.0 10. 10.48 .0 10.10.48.80 255 255.255.0 192.149.24.191 255.255.255.0 150.203.23.19 255.255.0.0 10.10.10.10 255.000 186.13.23.110 255.255.255.0 223.69.230 250 255 255.0.0 200.120.135.15 255.255.255.0 27 125 200 151 255.0.0.0 199 20 150 35 255.255 2550 191.55 165.135 255 255 2550 28 212 250 254 255 255 00
A supernet has the first address ( 192.168.16.0) netid length 22. The Supernet mask is Select one: a. 255.255.0.0 b. 255.255.192.0 C. 255.255.252.0 O d. 255.255.253.0
CIDR Notation LAN Network First Address 10.6.0.0/22 10.7.128.0/20 10.7.128.0 10.7.143.255 10.8.?.0/22 10.9.128.0/21 10.9.128.0 Last Address Number of Addresses Address 10.6.0.0 10.8.3.255
LAN 1 192168 10.16/28 2001.0B81.10-/64 GO/0 10.10.100/30 2001.088A1-/64 198.0.0.0/24 2001:DB8FF-/64 ISP1 GO/O PCA S1 G01 Corporate Network R1 G0/1 S0/0/1 $3 G0/2 101010 4/30 2001 DB8A.2 /64 S2 LAN 2 G0/0 192168 11.32/27 2001 DB8 1.11 /64 Custome 198.0.0 2001 088 ISP2 PC-B 1. Write the command to configure an IPV4 directly connected default static route on router R1 to forward the traffic through router ISP1. RI(config)# 2. Write the command to configure an IPV4 next-hop static route on router ISP1 to forward the traffic to LAN 1 network through router R1. ISPI(config)# 3. Write the command to configure an IPv6 next-hop flioating static default route on router R1 to forward the traffic through router ISP2 Configure the administrative distance of 5. R1(config)# A- B
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uuter620Networks%20-%20HandoutLpdf Network Addresses Using the IP address and subnet mask shown write out the network address 188.10.18.2 188. 10.0.0 255.255.0.0 10. 10.48.0 10.10.48.80 255.255.255.0 192.149.24.191 255.255.255.0 150.203.23.19 255.255.0.0 10.10.10.10 255.0.0.0 186.13.23.110 255.255.255.0 223.69.230.250 255.255 0.0 200.120.135.15 255.255.255.0 27.125.200 151 255.0.0.0 199.20.150 35 255 255.2550 191.55 165.135 255.255.255.0 28 212.250 254 25525500
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