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- 1. On the drawing attached, before any geometric controls are applied, what is the coaxility tolerance that is implied between the diameters?3. A strip of chicken skin was excised for mechanical testing in tension. The initial dimension of the rectangular specimen was 30 mm long and 15 mm wide, with average thickness of 3 mm. The mechanical testing was conducted at a rate of 5 mm/sec. The following data were obtained: gauge length, mm 20 22 24.2 26.3 27.9 30.1 force, N 0 0.8 2.7 7.9 12.9 19.6 a. Calculate the engineering stresses and strain from the information given and plot the stress-strain curve. Assume that 5 mm of the specimen length is clamped by the testing grip at each end, such that the initial gauge length of the specimen is 20 mm.On the drawing attached, before any geometric controls are applied, what is the coaxility tolerance is implied between the diamters?
- The following data were recorded during the tensile test of a 12.8 mm diameter stainless steel rod. The gauge length was 50.8 mm. Load Length Load Length mm mm 107.800 51.308 119,400 51.562 128,300 51.816 149,700| 52.832 50.800 50.825 12,700 25.400 50.851 38,100 50.876 50,800 76,200 89,100 92,700 102,500 51.181 124,700 56.642 50.902 50.952 159,000 53.848 160,400| 54.356 159,500 54.864 51.054 151,500 55.880 51.003 using the data above plot the stress-strain diagram and determine the following mechanical properties Q1 The proportional limit Q 2 The modulus of elasticity Q 3 yield point Q5 The Últimate Tensile Strength Q 4 yield strength at 0.2% offset Q 6 rupture strengthDesuon T EHide blocks Determine the Young's modulus of a metal alloy having the following tensile stress-strain diagram. ot yet nswered Stress-Strain Diagram Marked out of 5.00 1200 P Flag question 1000 800 1000 500 800 600 400 400 200 0.005 0.01 0.015 002 0.025 0.03 0.05 0.1 0.15 Strain (mm/mm) 0.2 0.25 Select one: O E = 1000 Mpa O E= 250 Gpa OE = 120 Gpa E = 50 Gpa E = 200 Gpa Stress (Mpa)The following data were recorded during the tensile test of a 12.8 mm diameter stainless steel rod. The gauge length was 50.8 mm. Load Length Load Length N N 50.800 107.800 51.308 50.825 119,400 51.562 128,300| 51.816 149,700 52.832 50.902 159,000 53.848 160,400 54.356 159,500 54.864 151,500 55.880 124,700 56.642 mm mm 12,700 25,400 38,100 50,800 76,200 89,100 92,700 102,500 | 51.181 50.851 50.876 50.952 51.003 51.054
- The shear modulus. G. of a material can be determined by applying a torque. T, on a cylindrical material specimen and measuring the angular twist, 0. The modulus can then be calculated from: G each measured variable (L. T.t. 0, R) is 3.4%. 3LT 2 Ree where R and Lare the specimen radius and length, respectively. The relative uncertainty in What is the total relative uncertainty in G? (Provide your amwer as a percentage using two decimal places. Do not include the % symbol.) 1226mechaWhat is Qh and Qc based on the table
- Asiacell 4,ll ON 76% D19:17 سؤال الواجب.docx Problem :- The following data was obtained tensile test on a specimen of 6 mm diameter and gauge length Lo=30 mm: load(KN) 0 40 80 95 90 135 150.2 145 130 120 elongation(mm) 0 0.022 0.13 0.25 0.55 2.01 3.88 4.12 5.22 6 Plot engineering and True (stress-strain) curves, then determine the (oy, ɛy), (ou, ɛu), (of, , ef), ductility , modulus of elasticity . Then select on the drawing (strain hardening (n)), (Necking), (uniform plastic region and non-uniform plastic region) and (elastic & plastic) region)?A tensile test was performed to find the stress-strain curve of a metal sample.Here are the results provided by the tensile testing machine.Suppose the results are free of errors. Elongation, 0 AL (cm) Applied force , F(N) 4.086 5.448 2.724 6.81 1.362 55571.1 61710.1 52930.5 68018.1 39498.3 Additional information : Lo : the length of the extensometer Lo = 5.42 cm A= 5.342 Questions : a) At. Using the 0.2% yield strength method, calculate the tensile strength of the metal sample. b) Find the modulus of resilience of the material under test. c) Calculate the allowable load for an object made of this metal using the parameters following: * Maximum stress: elastic limit Cross section: 10 mm2 Safety factor (or margin): 7 Calculate numerically with a minimum of four decimal places.. 2) A following figure and table display creep test data obtained from a uniaxial specimen having an initial gauge length of 2 cm. Calculate the steady-state creep rate. Length |(cm) 2.3 Time | (h) 2.25 2.004 2.2 100 2.010 200 2.020 400 2.030 1000 2000 2.045 2.075 2.1 2.05 4000 2.135 6000 2.193 7000 2.230 1.95 8000 2.300 1000 2000 3000 4000 5000 6000 7000 8000 Time (h) (rupture) | Length between the gauge marks (cm) 2.